Answer: 
Step-by-step explanation:
Given

We can write it as

Express x in terms of y

Replace y be x to get the inverse

To prove, it is inverse of f(x). 

So, they are inverse of each other.
The sum of polynomials involves adding the polynomials
The other polynomial is 
The sum of the polynomials is given as:

One of the polynomials is given as:

Represent the other polynomial with Q.
So, we have:

Substitute the expressions for P and Sum

Make Q the subject

Evaluate like terms

Hence, the other polynomial is 
Read more about polynomials at:
brainly.com/question/1487158
The answer is C because the x axis is 2 and the y axis is -2 so the answer is (2,-2).
Wouldn't it be. 8 pieces because you cut each sides into two pieces so like this. —|—. You'll end up having four square pieces, but count the pieces that creates an L shape.
best wishes good luck
Answer:

Step-by-step explanation:
Rewrite the system of equations as:

Subtract the second equation from the first to isolate
:

Plug in
into any of the equations above and solve for
:

Verify that the solution pair
works 
Therefore, the solution to this system of equations is:
