Answer:
False.
Step-by-step explanation:
If M(6, -2) were reflected across the line x = -3, then M' would be (0, -2) making the statement true.
#1 1.5x + 2.5y = 884.50
#2 x + y = 435
Remember, x represents the children and y represents the adult
The first equation represents the cost of tickets, while the second one represents the number of people.
Find x in equation #2 & plug it into equation #1.
(usually choose easiest equation to solve first, but it's your preference)
x + y = 435
x = 435 - y. ***
Use the equation*** above and plug it into equation #2.
Plugging in x, to solve for y:
1.5(x) + 2.5y = 884.50
1.5(435 - y) + 2.5y = 884.50
652.50 - 1.5y + 2.5y = 884.50
(subtract 652.50 from both sides)
-1.5y + 2.5y = 232
y = 232
Solve for x using equation #2 (or whichever you prefer) and plug in y.
x + y = 435
x + 232 = 435
(subtract 232 from both sides)
x = 203
There were 203 children and 232 adults at the pool that day.
Answer:
Step-by-step explanation:
Answer:
x2=81 x=9 and x=-9
x2=100 x=10 and x=-10
x=12 nothing you can solve for in this equation. X=12
Step-by-step explanation:
x2=81
Divide 81 by 2 and get x by it self
x2=100
Divide 100 by 2 and get x by it self
Answer:
h'(x) = (-x² ln x + x² + 1) / (x (x² + 1)^(³/₂))
Step-by-step explanation:
h(x) = ln x / √(x² + 1)
You can either use quotient rule, or you can rewrite using negative exponents and use product rule.
h(x) = (ln x) (x² + 1)^(-½)
h'(x) = (ln x) (-½) (x² + 1)^(-³/₂) (2x) + (1/x) (x² + 1)^(-½)
h'(x) = (-x ln x) (x² + 1)^(-³/₂) + (1/x) (x² + 1)^(-½)
h'(x) = (x² + 1)^(-³/₂) (-x ln x + (1/x) (x² + 1))
h'(x) = (1/x) (x² + 1)^(-³/₂) (-x² ln x + x² + 1)
h'(x) = (-x² ln x + x² + 1) / (x (x² + 1)^(³/₂))
