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3 years ago

10

Write the two statements that create the biconditional: There is traffic on the freeway if and only if there are a lot of cars o

n the freeway.

1 answer:

MariettaO [177]3 years ago

5 0

Answer:

there is traffic on the freeway

a lot of cars on the freeway

Step-by-step explanation:

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Pls help me! and no files and pls actually help me

crimeas [40]

Answer:

To find m ( slope) we'll use the Slope Formula:

$\boxed{\sf{Slope\:(m)}=\cfrac{y_2-y_1}{x_2-x_1}}$

<u>Subtract the numbers:-</u>

$\sf 7. \:m=\cfrac{4-2}{6-5} =\boxed{2}$

_______________

$\sf 8.\: m=\cfrac{-1-3}{2-6} =\boxed{1}$

_______________

$\sf 9.\: m=\cfrac{-4-(-2)}{3-1} =\boxed{-1}$

_______________

$\sf 10.\: m=\cfrac{0-3}{0-(-3)} =\boxed{-1}$

_______________

$\sf 11.\:m=\cfrac{4-2}{3-1} =\boxed{1}$

_______________

$\sf 12.\: m=\cfrac{1-7}{2-5} =\boxed{2}$

_______________

$\sf 13.\:m=\cfrac{11-9}{1-(-4)} =\boxed{\frac{2}{5}}$

_______________

$\sf 14.\:m=\cfrac{2-3}{3-5} =\boxed{\frac{1}{2}}$

_______________

$\sf 15.\: m=\cfrac{11-5}{2-9} =\boxed{-\frac{6}{7}}$

_______________

$\sf 16.\: m=\cfrac{-7-\left(-6\right)}{8-13}=\boxed{\frac{1}{5}}$

_______________

$\sf 17.\: m=\cfrac{4-4}{6-1} =\boxed{0}$

_______________

$\sf 18. \: m=\cfrac{2-(-7)}{5-5}=$

↑ Undefined

___________________________________

6 0

3 years ago

Jorden leaves home for school on his bike everyday at 6:00 AM, traveling at 32 km/h. one day he forgot his homework, which his m

densk [106]

Answer:

She caught up with Jordan at 6:39 AM

Step-by-step explanation:

We solve this question making linear functions for the distances that Jorden and his mom have driven, and then we equalize them to find the moment they caught up.

Jorden leaves home for school on his bike everyday at 6:00 AM, traveling at 32 km/h.

Her mom will have left 15 minutes after he left, when he will already have traveled $\frac{15*32}{60} = \frac{32}{4} = 8\text{km}$

So, his position after t minutes can be modeled by the following function:

$J(t) = 8 + 32t$

His mom

His mom goes after him starting from home, so the initial position is 0, with a velocity of 52 km/h. So her position can be modeled by the following function:

$M(t) = 52t$

At what time did she catch up with Jorden,

She catches up t minutes after 6:15 AM.

t is found when

$M(t) = J(t)$

So

$8 + 32t = 52t$

$20t = 8$

$t = \frac{8}{20}$

$t = 0.4$

0.4 of an hour is 0.4*60 = 24 minutes.

So she catched up with Jordan after 6:15 AM + 24 minutes = 6:39 AM

4 0

3 years ago

What is the volume of a regular pyramid having a base area of 24 in.² and a height of 6 inches?

Assoli18 [71]

Answer:

48 in³

Step-by-step explanation:

The volume (V) of a pyramid is calculated as

V = $\frac{1}{3}$ × area of base × height

here area of base = 24 and height = 6, so

V = $\frac{1}{3}$ × 24 × 6 = 8 × 6 = 48 in³

3 0

3 years ago

Solve for x. <br><br> x = ___

Mila [183]

Answer:

Solve y=x^2+2 for x.A.B.C.D

Step-by-step explanation:

sorry lamo

5 0

3 years ago

Given a table of values of a quadratic function, which of the following do you absolutely need in order to find its equation? *

nadya68 [22]

Answer:

The general form of a quadratic function is --> y = ax2 + bx + c

Since (0, -2) exists for the function, we can plug in those values:

-2 = a(0)2 + b(0) + c

-2 = 0 + 0 + c

-2 = c

So now our function so far is --> y = ax2 + bx - 2

We have two pairs of coordinates left: (-1, -8) and (3, -8).

First, plug in the first pair and simplify as much as you can:

-8 = a(-1)2 + b(-1) - 2

-8 = a - b - 2 ( add 2 to both sides )

-6 = a - b (stop here because we can't go further)

Second, plug in the second pair and simplify as much as you can:

-8 = a(3)2 + b(3) - 2

-8 = 9a + 3b - 2 ( add 2 to both sides )

-6 = 9a + 3b (stop here because we can't go further)

Now we have these two equations left:

a - b = -6

9a + 3b = -6

Now we solve for a and b using systems of equations, using one of three ways:

substitution

elimination

graphing (not my favorite, but it is doable)

Using substitution:

a - b = -6 can be rewritten as a = b - 6

plug into the second equation and solve for b

9(b - 6) + 3b = -6 (distribute the 9)

9b - 54 + 3b = -6 (combine all of the b's)

12b - 54 = -6 (add 54 to both sides)

12b = 48 (divide by 12 on both sides to isolate b)

b = 4

plug b into one of the original two equations

a - 4 = -6 (add 4 to both sides)

a = -2

The quadratic equation for this table is y = -2x2 + 4b - 2

6 0

3 years ago