Answer:
Solve for the first variable in one of the equations, then substitute the result into the other equation.
x
=
−
1
Step-by-step explanation:
So you need to come up with a perfect square that works for the x coefficients.
like.. (2x + 2)^2
(2x+2)(2x+2) = 4x^2 + 8x + 4
Compare this to the equation given. Our perfect square has +4 instead of +23. The difference is: 23 - 4 = 19
I'm going to assume the given equation equals zero..
So, If we add subtract 19 from both sides of the equation we get the perfect square.
4x^2 + 8x + 23 - 19 = 0 - 19
4x^2 + 8x + 4 = - 19
complete the square and move 19 over..
(2x+2)^2 + 19 = 0
factor the 2 out becomes 2^2 = 4
ANSWER: 4(x+1)^2 + 19 = 0
for a short cut, the standard equation
ax^2 + bx + c = 0 becomes a(x - h)^2 + k = 0
Where "a, b, c" are the same and ..
h = -b/(2a)
k = c - b^2/(4a)
Vertex = (h, k)
this will be a minimum point when "a" is positive upward facing parabola and a maximum point when "a" is negative downward facing parabola.
The answer is= n= 11/2 and in decimal it’s n=5.5
Explanation:
You first move the constant to the right
4n=16+6 you then calculate which will be 4n=22 and then you divide both sides
Step-by-step explanation:
2x²+3x-2=0
(2x-1)(x+2)
x+2=0
x=-2 (no, because x must be >0)
2x-1=0
2x=1
x=½ (yes, because x>0)
