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Darina [25.2K]
3 years ago
11

What quadrilateral has both diagonals bisecting each other but they are not congruent or perpendicular?

Mathematics
1 answer:
Bond [772]3 years ago
8 0

Answer:

A parallelogram with different side lengths.

Step-by-step explanation:

If we consider a parallelogram (not rectangle, not square, and not a rhombus), then its diagonals will bisect each other but would be not congruent or perpendicular. See attached image.

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150 - x = 87 what does x equal here ?
Ainat [17]

Answer:

x=63

Step-by-step explanation:

<em>Subtract by 150 from both sides of equation.</em>

<em>150-x-150=87-150</em>

<em>Simplify.</em>

<em>87-150=-63</em>

<em>-x=-63</em>

<em>Divide by -1 from both sides of equation.</em>

<em>-x/1=-63/-1</em>

<em>Simplify, to find the answer.</em>

<em>-63/-1=63</em>

<em>x=63 is the correct answer.</em>

<em>I hope this helps you, and have a wonderful day!</em>

5 0
3 years ago
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A group of students wanted to investigate the claim that the average number of text messages sent yesterday by
Likurg_2 [28]
First we need to write the null and alternate hypothesis for this case.

Let x be the average number of text message sent. Then

Null hypothesis: x = 100
Alternate hypothesis: x > 100

The p value is 0.0853

If p value > significance level, then the null hypothesis is not rejected. If p value < significance level, then the null hypothesis is rejected.

If significance level is 10%(0.10), the p value will be less than 0.10 and we reject the null hypothesis and CAN conclude that:
The mean number of text messages sent yesterday was greater than 100.

If significance level is 5%(0.05), the p value will be greater than 0.05 and we cannot reject the null hypothesis and CANNOT conclude that:
The mean number of text messages sent yesterday was greater than 100.
7 0
3 years ago
Could someone help me, please?
k0ka [10]

We can rewrite the expression under the radical as

\dfrac{81}{16}a^8b^{12}c^{16}=\left(\dfrac32a^2b^3c^4\right)^4

then taking the fourth root, we get

\sqrt[4]{\left(\dfrac32a^2b^3c^4\right)^4}=\left|\dfrac32a^2b^3c^4\right|

Why the absolute value? It's for the same reason that

\sqrt{x^2}=|x|

since both (-x)^2 and x^2 return the same number x^2, and |x| captures both possibilities. From here, we have

\left|\dfrac32a^2b^3c^4\right|=\left|\dfrac32\right|\left|a^2\right|\left|b^3\right|\left|c^4\right|

The absolute values disappear on all but the b term because all of \dfrac32, a^2 and c^4 are positive, while b^3 could potentially be negative. So we end up with

\dfrac32a^2\left|b^3\right|c^4=\dfrac32a^2|b|^3c^4

3 0
3 years ago
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maksim [4K]

Answer:

two of the sides are 21 m long and one of the sides is 28 m long

8 0
3 years ago
Algebra one quiz 12.2.3
Montano1993 [528]

Answer:

where is link

Step-by-step explanation:

6 0
3 years ago
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