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4 years ago

90x − 20 what is the constant term in this equation

Mathematics

2 answers:

Fittoniya [83]4 years ago

7 0

The constant term in the equation is -20 because you will always be subtracting 20 no matter how big x is

labwork [276]4 years ago

3 0

You can its a no soulution

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The population of Bloom Falls, Mass (population 937)is slowly moving to a

natka813 [3]

Answer:

Step-by-step explanation:

When the population drops by 4.5%, there will be (1 - 4.5%) = 0.955 portion of the original population staying. When it happens 3 years in a row with an original population of 937, there will be:

937*0.955*0.955*0.955 = 816.11

~816 people staying in Bloom Falls.

7 0

2 years ago

What is the volume of the figure?

Verdich [7]

Answer:

total volume = 225m^3

Step-by-step explanation:

try to cut it as 2 rectangular shape, bigger one with 6cm x 6cm, smaller one with 3cm x 3cm

volume 1 = 6 x 6 x 5 = 180m^3

volume 2 = 3 x 3 x 5 = 45m^3

3 0

3 years ago

A point X is 34m due east of a point Y.The bearing of a flagpole from X and Y are N18W and N40E respectively calculate the dista

neonofarm [45]

Answer:

The answer is "38.130".

Step-by-step explanation:

Given:

$Points (Y, X) \\\\F (flagpole)\ make\ a \ triangle$

Draw Y and X triangles on the underside, and F above them.

Because F is $18^{\circ}$ west from X, so FXY angle measurement $FXY = 72^{\circ}$ from X because F is located $40^{\circ}$ east of north from Y, then

measure of angle $FYX = 50^{\circ}$

the measure of angle $YFX = 58^{\circ}$ $(3 \angle \ of\ triangle = 180^{\circ})$

Using Law of Sines: $\frac{\sine 58^{\circ}}{34} = \frac{\sine 72^{\circ}}{YF}$

Cross Multiply:

$YF (\sin 58^{\circ}) = 34(\sin 72^{\circ})\\\\$

$YF = \frac{34 \sin 72^{\circ}}{\sin 58^{\circ}}\\\\ YF = \frac{34(.951)}{(.848)}\\\\ YF = 38.130$

4 0

3 years ago

Does anyone know how to do thesubstitution method?

Angelina_Jolie [31]

Hi!

<h3>How do we use the substitution method?</h3>

To solve using the substitution method, we first want to isolate any of the variables from one of two equations, and then you take the value of that and plug it into the other equation.

<h3>Given:</h3><h3> $y=4x-10$ </h3>

$y=-3x+4$

Normally, our step one would be to pick a variable and isolate it, but it looks like we already have the y-value in both equations isolated! So our step one is already done!

Plug the isolated variable into the other equation.

We will use the value of y in the first one, and plug it into the second.

The value of y is "4x - 10", so we will change "y" in the second equation to "4x - 10", like so:

$4x-10=-3x+4$