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3 years ago

PLEASE HELP V IMPORTANT the answers I input were just so I could see other questions.

Mathematics

1 answer:

marishachu [46]3 years ago

6 0

Step-by-step explanation:

(T-S)(2000), when T(x) and S(x) are functions, is equivalent to T(2000)-S(2000), which is 17-7=10

We know that T(x) is equal to everything else, and everything else is S(x)+G(x), so T(x)-S(x) = G(x), or dollars spent on general science

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Please help me thank you

Mashcka [7]

Answer:

f(2) 6x2= 12

f(-6) 6x-6=-36

f(5) 6x5=30

f(0) 6x0=0

f(10) 6x10=60

Step-by-step explanation:

it's really easy when they ask you this just put the number in parentheses instead of the x because x is an unknown number it's telling you to multiply the 6 by the number they give you

6 0

3 years ago

In a geometric sequence, the__ between consecutive terms is constant

kow [346]

Answer:

In a geometric sequence, the ratio between consecutive terms is constant.

Step-by-step explanation:

A geometric sequence is where you get from one term to another by multiplying by the same value. This value is known as the constant ratio, or common ratio. An example of a geometric sequence and it's constant ratio would be the sequence 4, 16, 64, 256, . . ., in which you find the next term by multiplying the previous term by four. 4 × 4 = 16, 16 × 4 = 64, and so on. So, in this sequence the constant ratio would be four.

3 0

3 years ago

Rationalise the equation : <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7By%20%5E%7B2%7D%20%7D%7B%20%5Csqrt%7Bx%5E%7B2%7D

Nat2105 [25]

Answer:

$\sqrt{x^2+y^2}-x$

Step-by-step explanation:

$\textsf{Mulitply by}\quad\dfrac{\sqrt{x^2+y^2}-x}{\sqrt{x^2+y^2}-x}:$

$\implies \dfrac{y^2}{\sqrt{x^2+y^2}+x} \times \dfrac{\sqrt{x^2+y^2}-x}{\sqrt{x^2+y^2}-x}$

$\implies \dfrac{y^2(\sqrt{x^2+y^2}-x)}{(\sqrt{x^2+y^2}+x)(\sqrt{x^2+y^2}-x)}$

$\implies \dfrac{y^2(\sqrt{x^2+y^2}-x)}{(\sqrt{x^2+y^2})^2-x^2}$

$\implies \dfrac{y^2(\sqrt{x^2+y^2}-x)}{x^2+y^2-x^2}$

$\implies \dfrac{y^2(\sqrt{x^2+y^2}-x)}{y^2}$

$\textsf{Cancel the common factor}\:y^2:$

$\implies \sqrt{x^2+y^2}-x$

6 0

3 years ago

Read 2 more answers

What is a 1/4 of ?/100

irakobra [83]

$\frac{1}{4}\cdot100=25$
......

8 0

4 years ago

Read 2 more answers

Please help <3 Paula is writing short, casual notes for how to find the inverse of a function, f. Those notes are shown below

NARA [144]

Answer:

(3rd listed choice) Paula's notes are incorrect. Step 4a should be "If the result does not define y as a function of x, then f does not have an inverse," and step 4b should be "If the result defines y as a function of x, then f has an inverse."

Step-by-step explanation:

If f(y) = x can be solved for a relation for y that is a function, then f(x) has an inverse. It will be the function defined by y.

6 0

3 years ago