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KatRina [158]
3 years ago
10

HELLLPPP ASAPPP PLSSS

Mathematics
1 answer:
xenn [34]3 years ago
5 0

Answer:

9.) .784 . 10) 0.29

Step-by-step explanation:

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If 2/3 of the girls have brown eyes and 1/4 of the girls have blue eyes what fraction of the girls in class have neither blue or
alex41 [277]
1/7th of girls have neither
4 0
3 years ago
The passing yards for the top 5 quarterbacks in the country are 3,832, 3,779, 3,655, 3,642, and 3,579. Find the variance and sta
Leviafan [203]

First get the average passing yards:

(3,832 + 3,779 + 3,655 + 3,642 + 3,579) / 5 = 3,697.4

Now get the squared residuals for each quarterback's passing yards. That is, compute the difference between each data and the average, then square the result. For example,

(3,832 - 3,697.4)^2 = 134.6^2 = 18,117.2

For the others, you should get squared residuals of

6,658.56

1,797.76

3,069.16

14,018.6

Take the sum of the squared residuals, then - since this is a sample, and not a population of all quarterbacks - divide the sum by 5 - 1 = 4 to get the variance:

(18,117.2 + 6,658.56 + 1,797.76 + 3,069.16 + 14,018.6)/4 = 10,915.3

The standard deviation is just the square root of the variance:

√(10,915.3) ≈ 104.48

5 0
3 years ago
Read 2 more answers
I AM STRUGGLING!!! PLEASE HELP ME!!
Butoxors [25]

Answer:

The answer would b 6.59 inches

4 0
2 years ago
Simplify the following expression 2[(7-3)^4 divided by 8] SHOW YOUR WORK! <br> someone pls help
kirill115 [55]

Answer:

64

Step-by-step explanation:

2(7-3)^4 divided by 8

2(4)^4 divided by 8

2(256) divided by 8

512 divided by 8

64

4 0
3 years ago
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A spherical balloon is inflated so that its volume is increasing at the rate of 3 ft3/min. How fast is the diameter of the ballo
beks73 [17]

When an spherical balloon volume is increasing at the rate of 3ft^3/min then the diameter of the balloon is increasing \frac{3}{2\pi }ft /min

How can we find the rate of change of balloon's diameter ?

The volume of a spherical balloon is v=\frac{4}{3} \pi r^3

In form of diameter we can write as

v=\frac{4}{3} \pi (\frac{D}{2} )^3\\=\frac{1}{6} \pi D^3

Now we will differentiate both sides wrt to t we get

\frac{dv}{dt} =\frac{1}{6} \pi 3D^2 \frac{dD}{dt} \\\frac{dD}{dt} =\frac{2}{\pi D^2} \frac{dv}{dt} \\\\when r=1\\D=2ft

Given in the question \frac{dv}{dt} =3ft^3/min

thus when we substitute the values we get

\frac{dD}{dt} =\frac{2}{\pi *2^2} (3)\\\frac{dD}{dt}=\frac{3}{2\pi }  ft/min

Learn more about the differentiation here:

brainly.com/question/28046488

#SPJ4

3 0
2 years ago
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