The coordinates are (rcos(6n),rsin(6n)) where r is the radius of the circle and n ranges from 0 to 59.
60 parts gives the angle 360/60=6 degrees, so multiples of this angle (6n) determine the coordinates.
When n=0, the coords are (r,0); when n=5, the coords are (r√3/2,r/2); when n=10 the coords are (r/2,r√3/2), etc.
Both problems can be solved similarly since both shapes are Quadrilateral hence the sum of thier interior angels is 360
5.)
(x)+(x)+(4x-26)+(2x+18)=360
8x-8=360
x-1=45
x=46
6.)
(2x)+(x)+(x+10)+(2x-16)=360
6x-6=360
x-1=60
x=61
Answer:
true
Step-by-step explanation:
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Answer:
127
Step-by-step explanation:
