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3 years ago

Help please? Its an exam.

Mathematics

1 answer:

nordsb [41]3 years ago

3 0

Answer:

I think x=9

2(3x)=54

3x=27

x=9

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Write the equation of the line in slope-intercept form Slope=5/3 Y-Intercept=4

Eddi Din [679]

Answer:

$\sf y=\dfrac{5}{3}x+4$

Step-by-step explanation:

Given:

$\textsf{slope of $\dfrac{5}{3}$, and a y-intercept of $4$}$

⇒ Slope-Intercept Form: y = mx + b

where:

m is the slope
b is the y-intercept (when x = 0)

Substitute the given values:

$\sf\\ \implies y=mx+b\\\\\implies y=\dfrac{5}{3}x+4$

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brainly.com/question/27803801

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2 years ago

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X over 3 is less then or equal to 5

Trava [24]

Answer:

x/3 ≤ 5

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2 years ago

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What is the answer ?

kari74 [83]

Answer:

Step-by-step explanation:

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4 years ago

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Franklin rolls a pair of six-sided fair dice with sides numbered 1 through 6.

Zarrin [17]

Answer:

The answer is 7/36.

Step-by-step explanation:

First, you find out how many possible outcomes there are from rolling a pair of dice. On one cube, you can roll a 1,2,3,4,5, or 6; so there are 6 outcomes. Since there are two cubes, you multiply 6 by itself to get a total of 36 possible outcomes. Next, you find the probability of the sum of the numbers rolled being an even number; the possibilities are 2,4,6,8,10, or 12, which is 6/36. The probability of rolling a multiple of 5; the one possibility is just 5, since we already accounted for rolling a 10 as an even number. So that is 1/36. The word or says that we add the two probabilities, so the final answer is 6/36+1/36=7/36.

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3 years ago

) Set up a double integral for calculating the flux of F=3xi+yj+zk through the part of the surface z=−5x−2y+2 above the triangle

Fynjy0 [20]

The surface (call it $S$ ) is a triangle with vertices at the points

$x=0,y=0\implies z=2\implies(0,0,2)$

$x=0,y=2\implies z=-2\implies(0,2,-2)$

$x=2,y=0\implies z=-8\implies(2,0,-8)$

Parameterize $S$ by

$\vec s(u,v)=(1-v)(2,0,-8)+v\bigg((1-u)(0,2,-2)+u(0,0,2)\bigg)=(2-2v,2v-2uv,-8+6v+4uv)$

with $0\le u\le1$ and $0\le v\le1$ . Take the normal vector to $S$ to be

$\vec s_v\times\vec s_u=(20v,8v,4v)$

Then the flux of $\vec F$ across $S$ is

$\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^1\int_0^1(6-6v,2v-2uv,-8+6v+4uv)\cdot(20v,8v,4v)\,\mathrm du\,\mathrm dv$

$=\displaystyle8\int_0^1\int_0^1(11v-10v^2)\,\mathrm du\,\mathrm dv=\boxed{\frac{52}3}$

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4 years ago