Answer:
The first listed equation is the correct equation to solve
The correct answer is: t = 5 seconds
Step-by-step explanation:
Let me mention first that there is an error in the statement that the gravitational pull of the Earth is 16 ft/s^2. It is in fact 32 ft/s^2, and the actual equation uses half of the acceleration multiplied by the square of the variable time, so it gives as final expression :

and we want to find the value/s for "t" that make this equation equal zero (when it reaches the ground and the object just touches the ground. This makes the equation we want to solve:

which solving for "t" becomes:

So we adopt the positive answer (positive time) since the negative value has no physical meaning for this problem.
That is: t = 5 seconds
10x - 12 + 10 = 18 - 20
10x - 2 = -2
10x = 0
x = 0
18÷(5-2)
18÷3
6 is the answer
Answer:
64
Step-by-step explanation:
First of all substitute the values to where ever you see their corresponding variables to make them multiply.
x = 9
y = 3
z = 2
so we get
8x as 8(9),
7z as 7(2)
2y as 2(3)
then the it's will be
8(9) - 7(2) + 2(3)
which is
72 - 14 + 6
finally we get
64
Added all that up and you get 680$
hope this helps