If a+b = 10 and a-b = 6 then find the value of ab
2 answers:
A + b = 10
a - b = 6
Add the equations together
2a = 16
Solve for a, divide 16 by 2.
a = 8
Then plug in a for one of the equations to get the value of b.
8 + b = 10
Subtract 8 from 10 to make b by itself.
b = 2
With a = 8 and b = 2, solve for ab
(8)(2) = 16.
ab = 16
Answer:
-0.641
-9.359
Explanation:
a+b = 10. Eq 1
ab = 6. Eq 2
From eq 1
a = 10 - b. Eq 3
From eq 3 on eq 2
(10-b) (b) = 6
10b - b^2 = 6
-b^2 + 10b - 6 = 0
b = (-10+-√{(10^2)-(4*-1-6)}) / (2*-1)
b = (-10 +-√{100-24)) / -2
b = (-10 +- √76) / -2
b = (10 +- 8.718)/-2
b1 = (10 - 8.718)/-2 = 1.282/-2 = -0.641
B2= (10 + 8.718)/2 = 18.718/-2 = -9.359
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