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vaieri [72.5K]
2 years ago
10

A rectangle has a length of 10cm and a width of 25cm

Mathematics
1 answer:
svet-max [94.6K]2 years ago
7 0

Answer:

What are you asking?

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A tube-feeding formula is administered to a patient via Gastrostomy at 75
melomori [17]

Answer:

97.5ml protein

Step-by-step explanation:

20hr * 75ml/hr = 1500ml

1500ml * .065 = 97.5ml protein

8 0
3 years ago
PLEASE HELP ILL GIVE BRAINLIEST Sara is making a cake in a trapezoid
alukav5142 [94]

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D im not sure just my opinion

5 0
2 years ago
What is the length of leg s of the triangle below?
vekshin1

Answer:

4 units

Step-by-step explanation:

Let ABC be isosceles right angled ∆ right angled at B

By Pythagoras theorem,

AC² = AB² + BC²

(√32)² = 4² + s²

32 = 16 + s²

s² = 32 - 16

s² = 16

s = √16

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Therefore s = 4 units

Hope it helps...

6 0
2 years ago
Consider the quadratic function: y = 2x^2 + 7x + 10
arsen [322]

Answer:

y-intercept: 10

concavity: function opens up

min/max: min

Step-by-step explanation:

1.) The definition of a y-intercept is what the resulting value of a function is when x is equal to 0.

Therefore, if the function's equation is given, to find y-intercept simply plug in 0 for the x-values:

y = 2x^2+7x+10 = 2(0)^2 + 7(0)+10 = 2(0) + 0 + 10 = 0 + 10 = 10

y intercept ( f(0) )= 10

2.) In order to find concavity (whether a function opens up or down) of a quadratic function, you can simply find the sign associated with the x^2 value. Since 2x^2 is positive, the concavity is positive. This is basically possible, since it is identifying any reflections affecting the y-values / horizontal reflections.

3.) In order to find whether a quadratic function has a maximum or minimum, you can use the concavity of the function. The idea is that if the function opens downwards, the vertex would be at the very top, resulting in a maximum. If a function was open upwards, the vertex would be at the very bottom, meaning there is a minimum. Like the concavity, if the value associated with x^2 is positive, there is a minimum. If it is negative, there is a maximum. Since 2x^2 is positive, the function has a minimum.

7 0
2 years ago
Write the standard form of the equation of the circle with the given characteristics. center: (0, 0); radius: 4
Delvig [45]
Hello :  here is a solution
x²+y² = 16
7 0
3 years ago
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