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Crazy boy [7]
2 years ago
7

Answer the precalculus question from khan academy pls! I will give brainliest and 5 stars. 30 points.

Mathematics
1 answer:
rosijanka [135]2 years ago
7 0

The value of f(h(2)) =2 and h(f(16))= 14

<h3>What is function?</h3>

Functions are the fundamental part of the calculus in mathematics. The functions are the special types of relations. A function in math is visualized as a rule, which gives a unique output for every input . Mapping or transformation is used to denote a function in math. These functions are usually denoted by letters . The domain is defined as the set of all the values that the function can input while it can be defined. The range is all the values that come out as the output of the function involved.

given:

f(x)= √x-1 , h(x)= x² + 5

Now,

f(h(2))= f( (2)² +5 )

=f(4+5)

=f(9)

=√9-1

= 3-1

=2

h(f(16)) = h( √16-1)

=h( 4-1)

=h(3)

=3² + 5

=9+5

=14

Learn more about function here:

brainly.com/question/12431044

#SPJ1

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Step-by-step explanation:

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<h2>Answer:</h2><h3>A. Domain </h3>

The domain of a function is the x-values that the graph applies to. This means that the domain is whatever x-values the graph crosses. All vertical parabolas (like the one pictured) have a domain of all reals. This is because any x-value could be plugged into the function and provide a y-value. while it may not seem like it, that graph will cover every single x-value in existence.

  • Domain = All reals

<h3>B. Range</h3>

The range is similar to the domain but is for y-values. So, the range is whatever y-values the graph applies to and crosses. As you can see from the graph, there are no y-values above 1. This means the range is y≤1.

  • Range = y ≤ 1

<h3>C. Increasing Interval</h3>

A graph is increasing when the y-values are increasing. So, on the parent function of a parabola, the graph increases to the right and decreases to the left. However, this graph is inverted and shifted to the left, so the interval will also be flipped and shifted. In this case, the graph increases from -∞ to 2.

  • Increasing Interval = [-∞, 2]

<h3>D. Decreasing Interval</h3>

The decreasing interval is very similar to the increasing interval. This interval applies when the y-values are decreasing as the x-values increase. For a parabola, the increasing and decreasing intervals always meet at the x-value of the vertex, which is 2 on this graph. The y-values decrease during the interval 2 to ∞.

  • Decreasing Interval = [2, ∞]

<h3>E. Opening</h3>

The direction of a parabola is decided by the sign (+ or -) of the leading coefficient. Positive coefficients open up and negative opens down. As you can see from the graph, the sides of the parabola point downwards. This means that the leading coefficient must be negative.

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A parabola will always only have a min or a max, never both. If a graph opens up it has a min because there is one y-value which is the minimum possible y-value. Graphs that open downwards have a maximum because there is one y-value that is the largest possible. So, this graph has a maximum of 1 because that is the largest possible y-value.

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You start at (5, 3). You move down 3 units and left 6 units. Where do you end?
raketka [301]

Answer:

(-1, 0)

Step-by-step explanation:

5 is the x value which is left and right, so you said u move left 6 units. Since the 5 is positive and left is negative; 5-6= -1. 3 is the y value which is up and down (vertical), so you said u move down 3 units, since the 3 is positive, when you move down that is negative; so 3-3=0.

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3 years ago
How many different right triangles are there with a hypotenuse of lenght 5 cm
Sveta_85 [38]

Answer:

Draw a horizontal line across a page of paper, somewhere in the middle. Mark a point A on the line, toward the left margin.

Spread open a compass to make good sized circle, but so that if the point of the compass is on the point you drew, the pencil fits on the page, both below the top edge and to the left of the right edge of the page. Draw the arc, from roughly the 12 O’Clock position over and down to the intersection of the line segment, at the 3 O’Clock position.

Call the opening of your compass, the radius of the arc you just drew, “5 units”.

Pick any point on the arc between the 12 and 3 positions, B. Drop a line down from that point B, perpendicular to the original horizontal line. Label the point that it intersects the horizontal line, C.

ABC is a right triangle with hypotenuse 5. Do this again with a point a little closer to the 3 O’Clock position. It’s another right triangle with hypotenuse 5.

Indeed, as you get closer to the right, along the arc, the height of the triangle declines, but the width of the triangle increases. The hypotenuse remains 5 in all cases. We picked points on the circle. We could have picked points on the horizontal line first, and raised perpendicular lines until they intersected the circle. Each point forms a distinct right triangle.

There are as many possible right triangles as there are possible points in a line segment.

Step-by-step explanation:

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-0.2 is not a possible value of x because lengths cannot be negative.
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