9514 1404 393
Answer:
8
Step-by-step explanation:
The Pythagorean theorem tells you of the relation ...
x² + 6² = 10² . . . . . . . . . squares of sides total to the square of hypotenuse
x² = 100 -36 = 64 . . . . . subtract 6²
x = √64 = 8 . . . . . . . . . . square root
The length of side x is 8 units.
Answer:
add 44 and 21 and you will get the answer
Let x = the width of the border
2x+23) by (2x + 33) are the overall dimensions of the pool and the border. Use the area to find x!
Overall area - pool area = 660 sq/ft (aggregate area)
(2x+23)*(2x+33) - (23*33) = 660
Solve.
4x^2+112x = 660
4x^2+112x−660=0 → subtract 660 on both sides
4(x−5)(x+33)=0 → factor
x−5=0 or x+33=0 → set both factors equal to 0
x = 5 or x = -33
In this case, we would use the positive solution, so the strip can be 5 ft. wide!
I hope this helps :)
Hey there!!
Let's take the first number an the smallest number as ' x '
Then, the second consecutive even integer would become ' x + 2 '
Third integer ' x + 4 '
Hence, adding them up, we get,
x + x + 2 + x + 4
... 3x + 6
This is equal to 4 times the smallest number.
We got the smallest number as ' x '
Hence, the final equation :
... 3x + 6 = 4x
Hope my answer helps!!
Answer:
<u>7 squares</u>
Step-by-step explanation:
<u>Key skills: Counting, Averages</u>
1) Based on what I counted, there are 11 columns, and 53 squares. If you want an average of 5 squares per column and you have 12 columns, the total number of squares you want is 60.
2) Since there are already 53 squares present, you need 60-53 = <u>7 squares</u> more.
<em>Hope you understood and have a nice day!!</em>
