It's C because for the perpendicular line, you need to construct cross points to draw it through.
- you start by drawing a random circle with F as the center, just as long as it intersects line DE
- Then you use the intersections of that circle to draw new circles starting at F.
- These new circles intersect at F and another point below DE.
- You draw the perpendicular line through F and the other point.
Answer:
The time at which the two trains will meet is 1 hour and 24 minutes
Step-by-step explanation:
The distances between the two trains = 196 miles
The direction of the two trains = Towards each other
The speed of one of the trains = 80 miles per hour
The speed of the other train = 60 miles per hour
Let 't' represent the time at which the two trains meet, we have;
80·t + 60·t = 196
∴ 140·t = 196
t = 196/140 = 7/5
The time at which the two trains will meet, t = 7/5 hours = 1.4 hours = 1 hour, 24 minutes.
Answer:
0.3073> 0.3037
Step-by-step explanation:
how can i explain more than 20 characters duh?
Answer:
Step-by-step explanation:
y = (-1/4)x - 4 has a y-intercept of (0, -4). Place a dark dot at (0, -4).
Now we use the info from the slope, -1/4:
Starting with your pencil point on the dot (0, -4), move the pencil point 4 units to the right and then 1 unit down. You will now be at (4, -5). Place a dark dot there.
Then draw a straight, solid line through (0, -4) and (4, -5).
To solve for proportion we make use of the z statistic.
The procedure is to solve for the value of the z score and then locate for the
proportion using the standard distribution tables. The formula for z score is:
z = (X – μ) / σ
where X is the sample value, μ is the mean value and σ is
the standard deviation
when X = 70
z1 = (70 – 100) / 15 = -2
Using the standard distribution tables, proportion is P1
= 0.0228
when X = 130
z2 = (130 – 100) /15 = 2
Using the standard distribution tables, proportion is P2
= 0.9772
Therefore the proportion between X of 70 and 130 is:
P (70<X<130) = P2 – P1
P (70<X<130) = 0.9772 - 0.0228
P (70<X<130) = 0.9544
Therefore 0.9544 or 95.44% of the test takers scored
between 70 and 130.
