Answer:
a) there is s such that <u>r>s</u> and s is <u>positive</u>
b) For any <u>r>0</u> , <u>there exists s>0</u> such that s<r
Step-by-step explanation:
a) We are given a positive real number r. We need to wite that there is a positive real number that is smaller. Call that number s. Then r>s (this is equivalent to s<r, s is smaller than r) and s is positive (or s>0 if you prefer). We fill in the blanks using the bold words.
b) The last part claims that s<r, that is, s is smaller than r. We know that this must happen for all posirive real numbers r, that is, for any r>0, there is some positive s such that s<r. In other words, there exists s>0 such that s<r.
Answer:
<em>6 days</em>
<em></em>
Step-by-step explanation:
Let the time taken by Carpenter working alone =
days
Then time taken by apprentice alone = Twice as that of taken by Carpenter = 2
days
Time taken working together = 2 days
Work done in one day working together = 
Work done in one day by Carpenter working alone = 
Work done in one day by apprentice working alone = 
Work done in one day by Carpenter working alone + Work done in one day by Carpenter working alone =
+
= Work done in one day working together = 

Time taken by Carpenter alone to complete the work = 3 days
Time taken by Apprentice alone to complete the work = 3
2= <em>6 days</em>
Answer:

Step-by-step explanation:
Given
← factor both numerator and denominator
=
← cancel common factor (1 - 2b) on numerator/denominator
=
← cancel 6 and 3 by 3
= 
Answer:
1/16 or 0.0625
Step-by-step explanation:
Im not sure but this may be the answer