Question

How do I solve the length of AC?​

Answer 1

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∆ABC and ∆ADE are similar triangles.

Thus ;

$\frac{AD}{AC} = \frac{DE}{BC} = \frac{AE}{AB}$

So :

$\frac{5}{3 + 2x} = \frac{4}{8}$

$\frac{5}{3 + 2x} = \frac{1}{2}$

Inverse both sides

$\frac{3 + 2x}{5} = \frac{2}{1}$

$\frac{2x + 3}{5} = 2$

Multiply sides by 5

$5 \times \frac{2x + 3}{5} = 5 \times 2$

$2x + 3 = 10$

Thus ;

$AC = 2x + 3 = 10$

$AC = 10$

Done...

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