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zhannawk [14.2K]
3 years ago
13

PLZ HELP IN QUIZ

Mathematics
2 answers:
MAXImum [283]3 years ago
7 0

Answer:

15 dimensional sides

Step-by-step explanation:

nikklg [1K]3 years ago
5 0

Answer:

1. Which statement would prove there is a. 2. There are two rectangles. Rectangle WXYZ has a length of 21 to two sides of another triangle, then the Which statement will always be true of the 6. The diagram shows the side lengths of two similar triangles. entre 15 km.

Step-by-step explanation:

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A 26-foot long ladder is leaning against a building
xxTIMURxx [149]

Answer:

13

Step-by-step explanation:

cos(60) =building height / 26

8 0
3 years ago
Read 2 more answers
What is 35.125 as a mixed number??
Sever21 [200]
The number can be separated into 35+0.125
0.125 can be rewritten as,
\frac{125}{1000}
So, the number can be rewritten;
35+\frac{125}{1000}
35\frac{125}{1000}
5 0
3 years ago
What is the image point of (-6, 9) after a translation left 4 uints and down 1 unit?
Alex17521 [72]

Answer:

(-10,8)

Step-by-step explanation:

So our original point is (-6,9).

A translation of 4 units to the left means that the x-value would go left by 4. In other words, we subtract 4 to -6. We subtract because going to the left means that it's going to the negative direction.

A translation of down 1 unit means that the y-value would go down by 1. In other words, we subtract 1. Again, we subtract because going downwards means that it's going to the negative direction.

Therefore, the new point would be:

(-6-4,9-1)\\=(-10,8)

6 0
3 years ago
James is considering buying a home priced at $104,000. If the current market
KatRina [158]
$106,000

In a buyers market, people that are buying a house can get it for a good price.
In a sellers market the person selling their house can make more.
8 0
3 years ago
① 5J+2S =12.20 ② 5J+ 10S =15.80 elimination method
hram777 [196]

Answer:

<h2>S = 9/20</h2><h2>J = 113/50</h2>

Step-by-step explanation:

5J +2S =12.20 ........(1)\\5J+10S=15.80......(2)\\Multiply \:equation \:(1)\:by\:the\:coefficient\:of\:x\:in equation\:(2)\\\\Multiply\:equation(2)\: by\: the\: coefficient\:of \:x\: in \:equation (1)\\\\5J +2S =12.20 ........(1) \times 5\\5J+10S=15.80......(2)\times 5\\\\25J+10S=61......(3)\\25J+50S = 79......(4)\\Subtract\:equation\:(4)\:from\: equation\: (3)\\-40S =-18\\\frac{-40S}{-40}=\frac{-18}{-40}\\  S = 9/20\\

Substitute \:9/20\:for \:x \:in\:equation\:(1)\:or \:equation\:(2)\\5J+2S = 12.20\\5J +2(9/20) =12.20\\5J +9/10=12.20\\5J=12.20-9/10\\5J=113/10\\Cross-Multiply\\50J = 113\\J = 113/50

4 0
3 years ago
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