Since cosecant is 1/sine and since cosine is just sine shifted by π/2, the reciprocal of the cosine, that is y = sec x must have the same range.
Answer:
30 m/s
Step-by-step explanation:
Let's say the distance from the first car to the intersection is x, and the distance from the second car to the intersection is y.
The distance between the cars can be found with Pythagorean theorem:
d² = x² + y²
Taking derivative with respect to time:
2d dd/dt = 2x dx/dt + 2y dy/dt
d dd/dt = x dx/dt + y dy/dt
We know that x = 200, dx/dt = -25, y = 150, and dy/dt = -50/3.
To find dd/dt, we still need to find d.
d² = x² + y²
d² = (200)² + (150)²
d = 250
Plugging everything in:
250 dd/dt = (200) (-25) + (150) (-50/3)
dd/dt = -30
The cars are approaching each other at a rate of 30 m/s at that instant.
5.692 is a terminating decimal because the decimal stopped at the digit of 2.
Hope this helps!
Answer:
I will try:
Step-by-step explanation:
Note: ∈ means 'belongs to the set of' and <em>R</em> is 'the set of all real numbers'
Inequality:
- Domain is: x ∈ <em>R</em>
- Range is: x ≥ -2
Set:
-Domain is: {x| x ∈ <em>R</em>}
- Range is: {y| y ≥ -2}
Interval:
- Domain is: (-∞,∞)
- Range is: [-2, ∞)
g(x) is stretched by a factor of 4 and translated 2 units down.