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d1i1m1o1n [39]
3 years ago
6

Kkkkkkkkkkkkkkkkkkkkkkk

Mathematics
2 answers:
svet-max [94.6K]3 years ago
6 0

Answer:

OKKKKKKKKKK:)

Step-by-step explanation:

KKKKKKKKKKKKK

d1i1m1o1n [39]3 years ago
3 0

Answer:

ikkkkkkkkkkkkkkkkkkkkkkk

Step-by-step explanation:

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Please help me understand.
USPshnik [31]

Answer:

B) 2

Below I wrote the steps on how I would find the answer.

Step-by-step explanation:

1. Yep, so basically cba = cbl + lba.

2. So you need to find x

3. So basically if you set up the equation 61x - 2 = 13x - 1 + 95

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5. X = 2

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According to the Bureau of Labor Statistics, the number of bank tellers in 2010 is expected to be 440,000. This is a decline of
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3 years ago
Can anyone help? I really need it
ElenaW [278]

Answer:

Step-by-step explanation:

Both equations should be in slop-intercept form (y=mx+b)

So add -2x to -6. Your equation should look like this

y=2x-6

In y=mx+b

b will fall on y-axis

mx is rise/run

So in the first equation plot -6 on y axis and go up 2 and over 1(because 2x is equivalent to 2/1 x)

In the second equation plot -1 on the y axis. Then go up 1 and over 3 from that point.

4 0
3 years ago
For 99 pts and Brainliest The vertices of kite DEFG are (5, 5), (8, 2), (5, -4), and (2, 2), respectively. Prove that the diagon
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Answer:

See below

Step-by-step explanation:

<em>Vector argument</em>

Vector DF is (5, -4) - (5, 5) = (0, -9).

Vector EG is (2, 2) - (8, 2) = (-6, 0).

The dot-product of these two vector is (0, -9)•(-6, 0) = 0·(-6) + (-9)·0 = 0.

When the dot-product of two vectors is zero, those vectors are at right-angles to each other. Therefore diagaonal DF ⊥ diagonal EG.

_____

<em>Alternate argument</em>

The x-coordinates of points D and F are the same, so diagonal DF is a vertical line. The y-coordinates of points E and G are the same, so diagonal EG is a horizontal line. Vertical lines are perpendicular to horizontal lines, so DF ⊥ EG.

3 0
3 years ago
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