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3 years ago

Help me plz it’s ASAP I need it

Mathematics

1 answer:

Lady_Fox [76]3 years ago

5 0

Answer:

Step-by-step explanation:

make a # bar and market up as a percentage do 25%, 50%, 75% then you put 15 where 75% is and from there you see where the #'s fit

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Which point on the number line represents the product of 4 and –2?

musickatia [10]

The point on the number line would be 2

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3 years ago

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What is the value of n so that the expression x^2+11x+n is a perfect square trinomial?

Sonbull [250]

N = 30 makes that a perfect square

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3 years ago

PLS I HAVE NO TIME I'LL MARK YOU BRAINLIST !!!

Umnica [9.8K]

2.-4 should be right for all of them

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2 years ago

evaluate the line integral ∫cf⋅dr, where f(x,y,z)=5xi−yj+zk and c is given by the vector function r(t)=⟨sint,cost,t⟩, 0≤t≤3π/2.

meriva

We have

$\displaystyle \int_C \vec f \cdot d\vec r = \int_0^{\frac{3\pi}2} \vec f(\vec r(t)) \cdot \dfrac{d\vec r}{dt} \, dt$

and

$\vec f(\vec r(t)) = 5\sin(t) \, \vec\imath - \cos(t) \, \vec\jmath + t \, \vec k$

$\vec r(t) = \sin(t)\,\vec\imath + \cos(t)\,\vec\jmath + t\,\vec k \implies \dfrac{d\vec r}{dt} = \cos(t) \, \vec\imath - \sin(t) \, \vec\jmath + \vec k$

so the line integral is equilvalent to

$\displaystyle \int_C \vec f \cdot d\vec r = \int_0^{\frac{3\pi}2} (5\sin(t) \cos(t) + \sin(t)\cos(t) + t) \, dt$

$\displaystyle \int_C \vec f \cdot d\vec r = \int_0^{\frac{3\pi}2} (6\sin(t) \cos(t) + t) \, dt$

$\displaystyle \int_C \vec f \cdot d\vec r = \int_0^{\frac{3\pi}2} (3\sin(2t) + t) \, dt$

$\displaystyle \int_C \vec f \cdot d\vec r = \left(-\frac32 \cos(2t) + \frac12 t^2\right) \bigg_0^{\frac{3\pi}2}$

$\displaystyle \int_C \vec f \cdot d\vec r = \left(\frac32 + \frac{9\pi^2}8\right) - \left(-\frac32\right) = \boxed{3 + \frac{9\pi^2}8}$

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2 years ago

X^2=12x-40 solve this equation using the quadratic formula

dybincka [34]

Answer:

Step-by-step explanation:

X²=12x-40

X²-12x+40=0

a=1 and b= -12 and c = 40

delta = b² - 4ac

delta = (-12)² - 4(1)(40) = 144 - 160 = - 16 = (4i)² ....i² = -1

x1= (12-4i)/2 =6-2i

x1= (12+4i)/2 =6+2i

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3 years ago

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