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user100 [1]
3 years ago
10

DF has midpoint E(1, -3). if ID(0, 2), what are the coordinates of F?

Mathematics
1 answer:
natita [175]3 years ago
3 0

Answer:

F is at (2, -8)

Step-by-step explanation:

use the midpoint formula:  (sum of x-values/2, sum of y-values/2)

let (x,y) = coordinate of pt F

(0+x/2) = 1;  x = 2

(2+y/2) = -3;   2 + y = -6;   y = -8

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