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3 years ago

Which value of the variable is a solution of the inequality t< -6?

1 answer:

6 0

The inequality <span>t < -6 states that t is a number that is less than -6, that is, is at the left side of -6 in the number line. Therefore from the options given, -7 in option B is the correct answer.</span>

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Standard deviation of a normal data distribution is a _______. Group of answer choices

FrozenT [24]

Answer:

Standard deviation of a normal data distribution is a measure of data dispersion.

Step-by-step explanation:

Standard deviation is used to measure dispersion which is present around the mean data.

The value of standard deviation will never be negative.

The greater the spread, the greater the standard deviation.

Steps-

1. At first, the mean value should be discovered.

2.Then find out the square of it's distance to mean value.

3.Then total the values

4.Then divide the number of data point.

5.the square root have to be taken.

Formula-

SD= $\sqrt{\frac{(\sum{x-x)^2} }{n-1}$

Advantage-

It is used to measure dispersion when mean is used as measure of central tendency.

5 0

3 years ago

What is the mean of the following set of numbers? 121, 347, 45, 21, 300, 614, 312, 333, 421

Norma-Jean [14]

The mean is 279.3 repeating.

5 0

3 years ago

Read 2 more answers

suppose you have three consecutive integers. The greatest of the three integers is twice as great as the sum of the first two. W

zvonat [6]

Answer:

0,1,2

Step-by-step explanation:

(x+2) = 2((x+1)+(x)

x+2 = 2x+2+2x

x+2 = 4x+2

-x -x

2 = 3x + 2

-2 -2

0/3 = 3x/3

0 = x

6 0

3 years ago

A sample of blood pressure measurements is taken for a group ofadults, and those values (mm Hg) are listed below. The values a

scoundrel [369]

Answer:

1. coefficient of variation(systolic) = 13.88%

2. coefficient of variation(diastolic) = 16.2%

3. The coefficients of variation for each data set are within 5 percentage points of each other Therefore the systolic measurements vary signifcantly less than the diastolic

Step-by-step explanation:

1. Mean of systolic = ( 117+126+158+96+157+122+116+134+127+122)÷10

= 127.5

Standard Deviation of systolic = (((117-127.5)^2 +(126-127.5)^2+(158-127.5)^2+ (96-127.5)^2 + (157-127.5)^2 + (122-127.5)^2 + (116-127.5)^2 +(134-127.5)^2 +(127-127.5)^2 +( 122-127.5)^2) ÷ 10)^(0.5)

SD = 17.7

coefficient of variation(systolic)

= Standard Deviation of systolic /mean of systolic

= $\frac{17.7}{127.5} * 100$

coefficient of variation(systolic) = 13.88%

2. Mean of diastolic = ( 80+77+76+51+90+89+60+64+72+83) ÷ 10

= 74.2

Standard Deviation of diastolic = (((80-74.2)^2 +(77-74.2)^2+(76-74.2)^2+ (51-74.2)^2 + (90-74.2)^2 + (89-74.2)^2 + (60-74.2)^2 +(64-74.2)^2 +(72-74.2)^2 +(83-74.2)^2) ÷ 10)^(0.5)

SD = 12

coefficient of variation(diastolic)

= Standard Deviation of diastolic /mean of diastolic

= $\frac{12}{74.2} *100$

coefficient of variation(diastolic) = 16.2%

3. The coefficients of variation for each data set are within 5 percentage points of each other Therefore the systolic measurements vary signifcantly less than the diastolic

8 0

3 years ago

What is the slope and y-intercept for the line represented by this equationn?

Mashutka [201]

The answer is A. slope = 7/3

y-intercept = -3

Good luck!

3 0

3 years ago