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pshichka [43]
3 years ago
8

A fair coin is tossed 20 times. The probability of getting the three or more heads in a row is 0.7870 and the probability of get

ting three or more heads in a row or three or more tails in a row is 0.9791.2
What is the probability of getting three or more heads in a row and three or more tails in a row?​
Mathematics
1 answer:
adelina 88 [10]3 years ago
7 0

Answer:

The  value is  P( H \  n \  T ) =  0.6049

Step-by-step explanation:

From the question we are told that

   The  number of times  is  n  =  20  

   The probability of getting three or more heads in a row is  P(H) =  0.7870

   The probability of getting three or more heads in a row or three or more tails in a row is    P(H \ u \   T )  =  0.9791

Generally given that it is a fair coin , then   P(H) = P(T) =  0.7870

Here  P(T) is  probability of getting three or more tails  in a row

Generally  the probability of getting three or more heads in a row and three or more tails in a row is mathematically represented as

        P( H \  n \  T ) =  P(H) + P(T) -  P( H \  u \  T )

=>   P( H \  n \  T ) =  0.7870  + 0.7870 -  0.9791

=>   P( H \  n \  T ) =  0.6049

 

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Answer:

310 inches²

Step-by-step explanation:

Given: A rectangular prism cage has a height of 28 inches.

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We know the area of base of rectangular prism is equal to the area of rectangle.

∴ Lets find out the lenght and width of rectangular prism.

Volume of rectangular prism= w\times l\times h

Where, w is width

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Answer:

x + 2

Step-by-step explanation:

If we know one of the factors, we should be able to use long division.

We can divide the trinomial by the binomial and find the other factor.

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