Question

A fair coin is tossed 20 times. The probability of getting the three or more heads in a row is 0.7870 and the probability of getting three or more heads in a row or three or more tails in a row is 0.9791.2
What is the probability of getting three or more heads in a row and three or more tails in a row?​

Answer 1

Answer:

The  value is  $P( H \ n \ T ) = 0.6049$

Step-by-step explanation:

From the question we are told that

   The  number of times  is  n  =  20  

   The probability of getting three or more heads in a row is  $P(H) = 0.7870$

   The probability of getting three or more heads in a row or three or more tails in a row is    $P(H \ u \ T ) = 0.9791$

Generally given that it is a fair coin , then   $P(H) = P(T) = 0.7870$

Here  P(T) is  probability of getting three or more tails  in a row

Generally  the probability of getting three or more heads in a row and three or more tails in a row is mathematically represented as

        $P( H \ n \ T ) = P(H) + P(T) - P( H \ u \ T )$

=>   $P( H \ n \ T ) = 0.7870 + 0.7870 - 0.9791$

=>   $P( H \ n \ T ) = 0.6049$