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CaHeK987 [17]
3 years ago
9

Someone plz help me please

Mathematics
1 answer:
Liula [17]3 years ago
3 0

Answer:

c and d

Step-by-step explanation:

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10. (a) Consider the following matrices: A = ( 2 ) B = (3) and C = (-3) w = Find the det(A). [1] (ii) Is the matrix A singular?
Viefleur [7K]

i) We have to find the determinant of A.

We can do this as:

\det(A)=|\begin{bmatrix}{3} & {6} \\ {1} & {-2}\end{bmatrix}|=3*(-2)-6*1=-6-6=-12

ii) We have to find if the matrix A is singular.

Singular matrix have determinant equal to 0.

This is not the case for A, as its determinant is -12. Then, A is not a singular matrix.

iii) We have to find the values of x and y so that AB = C.

We have to write the matrix multiplication and we will obtain a system of linear equations:

We can now solve the system of equations by adding 3 times the second equation to the first equation:

\begin{gathered} 3(x-2y)+(3x+6y)=3(-3)+(-3) \\ 3x-6y+3x+6y=-9-3 \\ 6x+0y=-12 \\ x=\frac{-12}{6} \\ x=-2 \end{gathered}

We can now use the second equation to find the value of y:

\begin{gathered} x-2y=-3 \\ x+3=2y \\ y=\frac{x+3}{2} \\ y=\frac{-2+3}{2} \\ y=\frac{1}{2} \end{gathered}

The values are x = -2 and y = 1/2.

iv) When we want to multiply two matrices, the required condition is that the number of columns of the matrix on the left is equal the number of rows of the matrix on the right.

In the case of A(2x2) and B(2x1), when we do A*B this condition is satisfied.

But when we try to multiply BA, the number of columns of B is not equal to the number of rows of A, so the matrix mulitplication is not possible.

Answer:

i) det(A) = -12

ii) A is not singular because singular matrices have determinant equal to zero.

iii) x = -2 and y = 1/2.

iv) Is not possible because the number of columns of the first matrix has to be equal to the number of rows of the second matrix.

6 0
1 year ago
Rent-Me Rent-A-Car charges $25.00 per day plus $0.14 per mile to rent an economy car. Better Deal Rental Car charges $23.00 per
zalisa [80]

Answer:

The number of miles at which a car rented from either company cost the same amount is <u>50 miles</u>.

Step-by-step explanation:

Let x represents the number of miles at which a car rented from either company cost the same amount. Therefore, we can have the following equation:

RC = 25 + 0.14x ....................... (1)

BC = 23 + 0.18x ...................... (2)

Where;

RC = Total cost of Rent-Me Rent-A-Car

BC = Total cost of Better Deal Rental Car

The the cost of the two companies equal where RC = BC. Therefore, we equate equations (1) and (2) and solve for x as follows:

25 + 0.14x = 23 + 0.18x

25 - 23 = 0.18x - 0.14x

2 = 0.04x

x = 2 / 0.04

x = 50

Therefore, the number of miles at which a car rented from either company cost the same amount is <u>50 miles</u>.

<u>Note:</u>

This can be confirmed for equations (1) and (2) individually by substituting for x = 50 as follows:

For equation (1):

RC = 25 + 0.14(50)

RC = 25 + 7

RC = 32

For equation (2):

BC = 23 + 0.18(50)

BC = 23 + 9

BC = 32

Therefore, RC = BC = 32 confirms the answer.

3 0
3 years ago
Write an expression that is equivalent to 30(x + y + 1)
Lerok [7]

Answer:

30x + 30y +30

Step-by-step explanation:

4 0
2 years ago
If B=A, where on the number line will B appear?
Temka [501]
If B = A than B will appear in exactly the same location as A

The answer is B.

If B was less than A it would apear on the left of A and if it was greater than A it would apear right from A.
6 0
3 years ago
Please help what is q-75=50
kogti [31]
You have to add 75 to Both sides and 50+75= 125 So q=125. Hope this helped!
4 0
4 years ago
Read 2 more answers
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