Question

What values of b satisfy 4(3b + 2)^2 = 64?

Answer 1

Answer:

b = $\frac{2}{3}$ or b = -2

Step-by-step explanation:

4(3b + 2)^2 = 64

Divide by 4 on both sides

(3b + 2)^2 = 16

Square root both sides

√(3b + 2)^2 = √16

3b + 2 = ±4

Subtract 2 on both sides

3b = ±4 - 2

Divide by 3 on both sides

b = (±4 - 2)/3

If 4 is positive, b is $\frac{2}{3}$

If 4 is negative, b is -2

Answer 2

Answer:

The value of 0 can satisfy b.

Step-by-step explanation:

4(3b + 2)^2 = 64

(12b + 8)^2 = 64

(12b + 8)^2 = 64

144b + 64 = 64

144b + 64 - 64 = 64 - 64

144b = 0

144b / 144 = 0 / 144

b = 0

So, the value of 0 can satisfy b.