2 years ago

Write the following in standard form: (x-4)^2 = 49

Mathematics

1 answer:

Korolek [52]2 years ago

8 0

Answer:

I have made it in picture hope it helps

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What is the slope of the line that contains the points (-2, 1) and (0, -3)?

sergeinik [125]

the answer is c. -2

to find slope you do

y2-y1/x2-x1

in this case it’s

-3-1/0- -2

which simplifies to

-4/2 = -2

6 0

2 years ago

Simplify EXPLAIN your answer.

krek1111 [17]

$\frac{x-5}{ x^{3} +27} + \frac{2}{ x^{2} -9} = \frac{x-5}{ x^{3}+27 } + \frac{2}{(x+3)(x-3)} \\ \\ long-division.. \\ (x^{3} +27)/(x+3) = x^{2} -3x+9 \\ \\ \frac{x-5}{(x+3)( x^{2} -3x+9)} + \frac{2}{(x+3)(x-3)} \\ \\ \frac{x-5}{(x+3)( x^{2} -3x+9)}* \frac{x-3}{x-3} + \frac{2}{(x+3)(x-3)} * \frac{x^{2} -3x+9}{ x^{2} -3x+9} = \frac{(x-5)(x-3)+2( x^{2} -3x+9)}{(x+3)(x-3)( x^{2} -3x+9)}$

$\frac{(x-5)(x-3)+2( x^{2} -3x+9)}{(x+3)(x-3)( x^{2} -3x+9)} = \frac{ x^{2} -8x+15+2x^{2} -6x+18}{(x+3)(x-3)( x^{2} -3x+9)} \\ \\ \frac{ 3x^{2} -14x+33}{(x+3)(x-3)( x^{2} -3x+9)}$