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2 years ago

13

Tia and Tom are making cupcakes. They need 3/4 a cup of flour and 1/3 cup of butter per batch. If they have 4 1/4 cups of flour

and 1 1/2 cups of butter, how many batches can they make?

1 answer:

expeople1 [14]2 years ago

3 0

Answer:

5

Step-by-step explanation:

You might be interested in

Find all polar coordinates of point P = (9, 75°).

zubka84 [21]

Answer:

1) (9, 75+360n)

2) (−9, 255+360n)

Step-by-step explanation:

(9, 75) is same as (9, 75 + 360)

so it would be (9, 435)

It can also be expressed as (-9, 75 + 180 degrees)

so (-9,255) degrees

In general, (9,75+360 n) for n≥0 represents half of the possible ways of representing the point : (9,75)

6 0

3 years ago

QUESTION 1 1 POINT<br> Factor: 27m3<br> 64.<br> Provide your answer below:<br> Content attribution

pickupchik [31]

Answer:

$\boxed{ \bold{ \boxed{ \sf{(3m - 4)(9 {m}^{2} + 12m + 16)}}}}$

Step-by-step explanation:

$\sf{27 {m}^{3} - 64}$

$\dashrightarrow{ \sf{( {3m)}^{3} - {(4)}^{3} }}$

Use the formula of a³ - b³ = ( a - b) ( a² + ab + b² )

$\longrightarrow{ \sf{(3m - 4)(3 {m}^{2} + 3m \times 4 + {4}^{2} }})$

$\longrightarrow{ \sf{(3m - 4)( {9m}^{2} + 12m + 16}})$

Hope I helped!

Best regards! :D

5 0

3 years ago

Craig made 60% of 80 free throw attempts this season how many free throws has he made

Svetllana [295]

Answer:

<em>48</em>

Step-by-step explanation:

60% of 80 is the same as 60% times 80.

60% of 80 =

= 60% * 80

= 0.60 * 80

= 48

6 0

3 years ago

Read 2 more answers

The earth is approximately 92,900,000 miles from the sun. If 1 mile = 1.61 x 103 m, what is the distance to the sun in meters?

Dmitriy789 [7]

Answer:

here you go

Step-by-step explanation:

5 0

3 years ago

The life of a red bulb used in a traffic signal can be modeled using an exponential distribution with an average life of 24 mont

BartSMP [9]

Answer:

See steps below

Step-by-step explanation:

Let X be the random variable that measures the lifespan of a bulb.

If the random variable X is exponentially distributed and X has an average value of 24 month, then its probability density function is

$\bf f(x)=\frac{1}{24}e^{-x/24}\;(x\geq 0)$

and its cumulative distribution function (CDF) is

$\bf P(X\leq t)=\int_{0}^{t} f(x)dx=1-e^{-t/24}$

• What is probability that the red bulb will need to be replaced at the first inspection?

The probability that the bulb fails the first year is

$\bf P(X\leq 12)=1-e^{-12/24}=1-e^{-0.5}=0.39347$

• If the bulb is in good condition at the end of 18 months, what is the probability that the bulb will be in good condition at the end of 24 months?

Let A and B be the events,

A = “The bulb will last at least 24 months”

B = “The bulb will last at least 18 months”

We want to find P(A | B).

By definition P(A | B) = P(A∩B)P(B)

but B⊂A, so A∩B = B and

$\bf P(A | B) = P(B)P(B) = (P(B))^2$

We have

$\bf P(B)=P(X>18)=1-P(X\leq 18)=1-(1-e^{-18/24})=e^{-3/4}=0.47237$

hence,

$\bf P(A | B)=(P(B))^2=(0.47237)^2=0.22313$

• If the signal has six red bulbs, what is the probability that at least one of them needs replacement at the first inspection? Assume distribution of lifetime of each bulb is independent

If the distribution of lifetime of each bulb is independent, then we have here a binomial distribution of six trials with probability of “success” (one bulb needs replacement at the first inspection) p = 0.39347

Now the probability that exactly k bulbs need replacement is

$\bf \binom{6}{k}(0.39347)^k(1-0.39347)^{6-k}$

<em>Probability that at least one of them needs replacement at the first inspection = 1- probability that none of them needs replacement at the first inspection. </em>

This means that,

<em>Probability that at least one of them needs replacement at the first inspection = </em>

$\bf 1-\binom{6}{0}(0.39347)^0(1-0.39347)^{6}=1-(0.60653)^6=0.95021$

5 0

3 years ago