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Vitek1552 [10]
3 years ago
15

Please help ASAP thanks!!

Mathematics
1 answer:
Dimas [21]3 years ago
4 0
To find the total area. find the sum of the area of the rectangle and the triangle.

Rectangle area:  A = lw  or A = 8cm(4cm) = 32 cm²

Triangle Area is defined by A = \frac{b(h)}{2} where b = base of the triangle and h = height of the triangle.   Since our triangle is a right triangle, the base and height of the triangle are the two legs of the right triangle.  One of the legs has a measure of 3, but we don't see the measure of the other leg.  It is actually 4cm though... Do you see that it is just the opposite side of the rectangle already showing a measure of 4 cm.. We know that opposite sides of rectangles have the same measure.

So in our triangle b = 3cm and h = 4cm and A = \frac{3(4)}{2}= 6cm²

Total Area would be A = 32cm² + 6cm² = 38cm²
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Identify a pattern in the given list of numbers. Then use this pattern to find the next number.​ (More than one pattern might​ e
KatRina [158]
I'm not sure what the equation would be, but its the number multiplied by two, and It keeps accumulating so maybe yx2?
6 0
3 years ago
What is the sum of (-2)+(-2)
Nadya [2.5K]

Answer:

-4

Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
A random sample of 12 supermarkets from Region 1 had mean sales of 84 with a standard deviation of 6.6. A random sample of 17 su
Sladkaya [172]

Answer:

We conclude that there is no difference in potential mean sales per market in Region 1 and 2.

Step-by-step explanation:

We are given that a random sample of 12 supermarkets from Region 1 had mean sales of 84 with a standard deviation of 6.6.

A random sample of 17 supermarkets from Region 2 had a mean sales of 78.3 with a standard deviation of 8.5.

Let \mu_1 = mean sales per market in Region 1.

\mu_2  = mean sales per market in Region 2.

So, Null Hypothesis, H_0 : \mu_1-\mu_2 = 0      {means that there is no difference in potential mean sales per market in Region 1 and 2}

Alternate Hypothesis, H_A : > \mu_1-\mu_2\neq 0      {means that there is a difference in potential mean sales per market in Region 1 and 2}

The test statistics that will be used here is <u>Two-sample t-test statistics</u> because we don't know about population standard deviations;

                            T.S.  =  \frac{(\bar X_1 -\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+ {\frac{1}{n_2}}} }   ~  t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean sales in Region 1 = 84

\bar X_2 = sample mean sales in Region 2 = 78.3

s_1  = sample standard deviation of sales in Region 1 = 6.6

s_2  = sample standard deviation of sales in Region 2 = 8.5

n_1 = sample of supermarkets from Region 1 = 12

n_2 = sample of supermarkets from Region 2 = 17

Also, s_p=\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times  s_2^{2}  }{n_1+n_2-2} }  = s_p=\sqrt{\frac{(12-1)\times 6.6^{2}+(17-1)\times  8.5^{2}  }{12+17-2} } = 7.782

So, <u><em>the test statistics</em></u> =  \frac{(84-78.3)-(0)}{7.782 \times \sqrt{\frac{1}{12}+ {\frac{1}{17}}} }  ~   t_2_7

                                   =  1.943  

The value of t-test statistics is 1.943.

 

Now, at a 0.02 level of significance, the t table  gives a critical value of -2.472 and 2.473 at 27 degrees of freedom for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of t, so we have<u><em> insufficient evidence to reject our null hypothesis</em></u> as it will not fall in the rejection region.

Therefore, we conclude that there is no difference in potential mean sales per market in Region 1 and 2.

6 0
3 years ago
Ms santos seashells into 4 row she puts 6 seashells in each row how many seachells are there altogether
kati45 [8]
4 rows and 6 seashells in each row. 
Row 1: 0 0 0 0 0 0
Row 2: 0 0 0 0 0 0
Row 3: 0 0 0 0 0 0
Row 4: 0 0 0 0 0 0

You add all of them together 6+6+6+6=24 
Or you could do 6x4 and your answer would be 24
So the answer to the question is 24 seashells. 
3 0
2 years ago
How bout this 1? yaall kno it
Nana76 [90]
I’m so sorry i don’t know
5 0
2 years ago
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