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2 years ago

What is tan(x) equal to? 1 2 sin(x) cos(x) sin(x)/cos(x)

Mathematics

1 answer:

mash [69]2 years ago

8 0

Answer: sin(x) / cos(x)

Step-by-step explanation: This is just a trigonometric identity you should have memorized :)

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Which number line shows 1 to 4 divided into fourths?

romanna [79]

Answer:

the second one dose I believe

3 0

2 years ago

A math teacher was frustrated at the number of students leaving their graphing calculator behind in her classroom at the end of

AleksAgata [21]

Answer:

The 99% confidence interval for the proportion of all students at this school who have their names written on their graphing calculators is (0.4652, 0.8148).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

A random sample of 50 students is selected, and of the students questioned, 32 had their names written on their graphing calculators.

This means that $n = 50, \pi = \frac{32}{50} = 0.64$

99% confidence level

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.64 - 2.575\sqrt{\frac{0.64*0.36}{50}} = 0.4652$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.64 + 2.575\sqrt{\frac{0.64*0.36}{50}} = 0.8148$

The 99% confidence interval for the proportion of all students at this school who have their names written on their graphing calculators is (0.4652, 0.8148).

8 0

2 years ago

Ms. Ramos buys a rare painting for m dollars. She sells it for 5 times the amount she paid for it, or 5m. Her profit is

kotegsom [21]

I’m pretty sure the answer is 4m/2

3 0

2 years ago

Read 2 more answers

HeLp pLzZzZzZzZzZzZzZzZzZ

Gnoma [55]

Answer:

Step-by-step explanation:

Problem One (left panel)

Question A

The y intercept happens when x = 0
That being said, the y intercept is 50. It was moving when the timing began.

Question B

The rate of change = (56 - 52)/(3 - 1) = 4/2 = 2 miles / hour^2 (you have a slight acceleration.

Question C

60 = a + (n-1)d
60 = 50 + (n - 1)*2
10/2 = (n - 1)*2/2
5 = n - 1
6 = n

The way I have done it the domain is n from 1 to 6

Question 2 (Right Panel)

Question A

The equation for the table is f(x) = 3x - 3 which was derived simply by putting all three points into y = ax + b and solving.

f(0) = ax + b
-3 = a*0) + b
b = - 3
So far what you have is
f(x) = ax - 3
f(-1) = a*(-1) - 3 but we know (f(-1)) = -6
- 6 = a(-1) - 3 add 3 to both sides
-6 +3 = a(-1) -3 + 3
-3 = a*(-1) Divide by - 1
a = 3
f(x) = 3x - 3 Answer for f(x)
The slope of f(x) = the coefficient in front of the x
f(x) has a slope of 3
g(x) has a slope of 4

Part B

f(x) has a y intercept of - 3
g(x) has a y intercept of -5
f(x) has the greater y intercept.
-3 > - 5

7 0

2 years ago

I need help. What is 9 - 3 / 1/3 + 1?

Allushta [10]

6/ 2/3 that the answe ti that that should be the answer

5 0

2 years ago

Read 2 more answers