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frosja888 [35]
3 years ago
9

Graph: y - 3 = 1/2 (x + 2)

Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
6 0

Answer:

Slope: \frac{1}{2}

Y-intercept: (0,4)

Step-by-step explanation:

Put the equation into y = mx + b form, which is y = \frac{1}{2} +4. Then create a table.

X: -2, -1, 0, 1, 2

Y: 3, \frac{7}{2}, 4, \frac{9}{2}, 5

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In a small chess tournament, 20 matches were played. Find out how many people were involved if it is known that each participant
Nina [5.8K]

Answer:

<em>5</em><em> players participated in the tournament.</em>

Step-by-step explanation:

In a small chess tournament, 20 matches were played.

Let us assume that n number of players participated in the tournament

As in each game 2 players play, so the number of ways they can play is,

=\ ^nC_2

As they played 2 games with every other participant in the tournament.

So the total number of games is,

=\ 2\times ^nC_2

But it is given to be 20, so

\Rightarrow \ 2\times ^nC_2=20

\Rightarrow \ ^nC_2=10

\Rightarrow \dfrac{n!}{2!(n-2)!}=10

\Rightarrow \dfrac{n(n-1)}{2}=10

\Rightarrow {n(n-1)=20

As 5\times 4=20, so we get n=5.

Therefore, 5 players participated in the tournament.

5 0
3 years ago
Read 2 more answers
For the function F defined by F(x)=x2−2x+4, find F(−2).
Kruka [31]

Answer:

12

Step-by-step explanation:

x^2-2x+4  replace -2 for x

-2^2-2(-2)+4

4+4+4

12

4 0
3 years ago
Read 2 more answers
Please helppppppp meeeeeeeeeeee
Paha777 [63]

Answer:

the answer is the third one

Step-by-step explanation:

3 0
3 years ago
Solve the following equation 5(y+4) =4(y+5)
kvv77 [185]

Answer:

Step-by-step explanation:

5(y+4) = 4(y+5)

5y+20 = 4y + 20

5y = 4y

y=0

6 0
4 years ago
If 1 ft = 1.894 x 10​ -4​miles, convert 20.0 inches to miles
Yakvenalex [24]

Answer:

3.1567 * 10^-4 miles

Step-by-step explanation:

1 ft = 1.894 * 10^-4 miles , so

1 inch = 1.894 * 10^-4 / 12  miles

= 0.15783 * 10^-4

= 1.5783* 10^-5 miles  ( in scientific form).

Multiplying this by 20 we get

31.567 * 10^-5

= 3.1567 * 10^-4 miles.

3 0
3 years ago
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