Answer:
Step-by-step explanation:
The value of the function f(x) at x=a can be determined by substituting a instead of x into the function expression.
1. When x=-1, then
f(-1)=2\cdot (-1)^3-3\cdot (-1)^2+7=-2-3+7=2.
2. When x=1, then
f(1)=2\cdot 1^3-3\cdot 1^2+7=2-3+7=6.
3. When x=2, then
f(-1)=2\cdot 2^3-3\cdot 2^2+7=16-12+7=11.
The value of x is 1/13 (4th choice)
Step-by-step explanation:
![{a}^{ \frac{m}{n} } = \sqrt[n]{ {a}^{m} }](https://tex.z-dn.net/?f=%20%7Ba%7D%5E%7B%20%5Cfrac%7Bm%7D%7Bn%7D%20%7D%20%20%3D%20%20%5Csqrt%5Bn%5D%7B%20%7Ba%7D%5E%7Bm%7D%20%7D%20)
If 14^x = ¹³√14, what value of <em>x </em>makes this equation true?
![\sqrt[13]{14} = {14}^{x} \\ \sqrt[13]{14} = {14}^{ \frac{1}{13} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B13%5D%7B14%7D%20%20%3D%20%20%7B14%7D%5E%7Bx%7D%20%20%5C%5C%20%20%5Csqrt%5B13%5D%7B14%7D%20%20%3D%20%20%7B14%7D%5E%7B%20%5Cfrac%7B1%7D%7B13%7D%20%7D%20)
So, the value of <em>x</em> is 1/13 (4th choice)
<em>Hope</em><em> </em><em>it </em><em>helpful </em><em>and </em><em>useful </em><em>:</em><em>)</em>
To get the extrema, derive the function.
You get y' = 2x^-1/3 - 2.
Set this equal to zero, and you get x=0 as the location of a critical point.
Since you are on a closed interval [-1, 1], those points can also have an extrema.
Your min is right, but the max isn't at (1,1). At x=-1, you get y=5 (y = 3(-1)^2/3 -2(-1); (-1)^2/3 = 1, not -1).
Thus, the maximum is at (-1, 5).
Answer:
The answer is x + 160 = 459
Step-by-step explanation:
You can find this answer by understanding what the variable is. Once you find that the rest is easy. You know that the cost of the peak II is $459. You also know that the peak II is $160 more than rider/variable so, 459 - 160 = 299
