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sweet [91]
3 years ago
10

I need all questions answered~

Mathematics
1 answer:
Vika [28.1K]3 years ago
7 0

Answer:

1.

c = 400.(1.03) {}^{m}  \\ when \: m = 12 \: months \\ c = 400 \times (1.03) {}^{12}  \\ c = 570  \: customers

2.

c = 400.(1.03) {}^{m}  \\ m = 12 \times y = 12y \\ c = 400.(1.03)  {}^{12y}

3.

y = 100 \\ c = 400.(1.03) {}^{(12 \times 100)}  \\ c = 1 \times  {10}^{18}  \: customers

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Nathaniel bought 3 hamburgers and 2 orders of fries for $12.50. Liam bought 2 hamburgers and 4 orders of fries for $13. How much
Nina [5.8K]

The cost of an order of 1 hamburger and 2 orders of fries cost which Nathaniel and Liam bought is $6.5.

<h3>What is system of equation?</h3>

A system of equation is the set of equation in which the finite set of equation is present for which the common solution is sought.

Let the cost of 1 hamburger is x dollar and 2 orders of fries is y dollars. Nathaniel bought 3 hamburgers and 2 orders of fries for $12.50. Thus,

3x+2y=12.5

Solve this equation as,

2y=12.5-3x\\y=\dfrac{12.5-3x}{2}                        .....1

Liam bought 2 hamburgers and 4 orders of fries for $13. Thus,

2x+4y=13

Put the value of y in this equation and solve it further,

2x+4(\dfrac{12.5-3x}{2})=13\\2x+25-6x=13\\-4x=13-25\\-4x=12\\x=\dfrac{12}{4}\\x=3

Put this value of x in equation 1,

y=\dfrac{12.5-3\times3}{2}\\y=\dfrac{3.5}{2}\\y=1.75

The cost of an order of 1 hamburger and 2 orders of fries is,

C=3\times 1+2\times1.75\\C=3+3.5\\C=6.5

Thus, the cost of an order of 1 hamburger and 2 orders of fries cost which Nathaniel and Liam bought is $6.5.

Learn more about the system of equations here;

brainly.com/question/13729904

#SPJ1

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