<span>The function g(x) is obtained by adding 3 to f(x).
The vertex of f(x) is at (0,0), and the vertex of g(x) is at (0,3). This means that 3 points should be adding to f(x) to achieve g(x); this shifts f(x) upwards 3 points.</span>
Answer: $20.82 per hour
Step-by-step explanation:
Answer:
17/7
Step-by-step explanation:
Answer:
In this case we use the Poisson distribution because we are talking about the occurrence of an event (number of tracks) over a specified interval (in this case an area interval).
The probability of the event occurring x times over an interval is:
P(x) = nˣ × e⁻ⁿ ÷ x!
where n is the mean.
a) P(7) = 6⁷ × e⁻⁶ ÷ 7! = 0.1376
b) P(x ≥ 3) = 1 - P(x < 3) = 1 - P(2) - P(1) - P(0)
P(2) = 6² × e⁻⁶ ÷ 2! = 0.0446
P(1) = 6¹ × e⁻⁶ ÷ 1! = 0.0149
P(0) = 6⁰ × e⁻⁶ ÷ 0! = 0.0025
P(x ≥ 3) = 0.9380
c) P(2 < x < 7) = P(3) + P(4) + P(5) + P(6) = 0.0892 + 0.1339 + 0.1606 + 0.1606 = 0.5443
d) The mean is going to be 6.
e) The standard deviation is √n = √6 = 2.4
So consecutive intergers are 1 away from each other so
the numbers are
x,x+1,x+2
if the product (multily) of 2 smaeller is 5 less than 5 times largest so
(x times (x+1)) is 5 less than 5 times (x+2)
(x times (x+1))=-5+5(x+2)
pemdas
distribute using distributiver property
a(b+c)=ab+ac so
x times (x+1)=x^2+x
5(x+2)=5x+10
we have
x^2+x=-5+5x+10
add like terms
x^2+x=5x+5
subtract (5x+5) from both sides
x^2-4x-5=0
factor by find what 2 numbers add to -4 and multply to get -5
numbers are 1 and -5
so we do
(x+1)(x-5)=0
sete each to zero
x+1=0
x-5=0
x+1=0
sbtract 1
x=-1
we want positie so thisis wrong answer
x-5=0
add 5
x=5
subsitute
x,x+1,x+2
5,5+1,5+2
5,6,7
smalles is 5
