Well, we know the cyclist left the western part going eastwards, at the same time the car left the eastern part going westwards
the distance between them is 476 miles, and they met 8.5hrs later
let's say after 8.5hrs, the cyclist has travelled "d" miles, whilst the car has travelled the slack, or 476-d, in the same 8.5hrs
we know the rate of the car is faster... so if the cyclist rate is say "r", then the car's rate is r+33.2
thus

solve for "r", to see how fast the cyclist was going
what about the car? well, the car's rate is r + 33.2
Answer:
9. 1.24 mL
10. $5.93
Step-by-step explanation:
<u>Question 9:</u>
If the dosage of medicine is 0.01 mL per pound of weight of the patient, and the patient's weight is 124 pounds, we can set up an equation to solve for how much medicine the patient would need to take:
Dosage of medicine per pound of body weight x Total body weight = Total medicine required
OR
0.01 * w = m,
where w is total body weight and m is total medicine required.
To solve for the dosage the patient needs, just plug the numbers into the right places (124 for w and leave m as it is):
0.01 * 124 = m
1.24 = m
Therefore, a patient with a body weight of 124 pounds would need a 1.24 mL dosage.
<u>Question 10:</u>
To make the multiplication easier, we could rewrite 15% as 0.15 ( because 15% = 15/100):
0.15 * Total bill = Total tax payed for bill (Also can be written as
)
OR
0.15*39.51 = Total tax
5.9265 = Total tax
5.93 = Total tax <-------- (rounded)
Step-by-step explanation:
Given 
To get g(x), we will have to integrate g'(x)

If g(1) = 0, this means at x = 1, g(x) = 0
0 = -1⁻¹ + C
C= 1
Substitute C = 1 into the function
g(x) = -x⁻¹ + 1
If g(2) = 0, this means at x = 2, g(x) = 0
0 = -2⁻¹ + C
C= 2⁻¹
C = 1/2
Substitute C = 2 into the function
g(x) = -x⁻¹ + 1/2
- 8(7k-5) + 7(7k-7) = 1 - 5k - k - 7
- 56k + 40 + 49k - 49 = 1 - 6k - 7
13k = 3
k = 3/13
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