2 years ago

5. The coefficient of x7 in the polynomial then7x17 - 17x11 + 27x5 - 7 is

Mathematics

1 answer:

Zinaida [17]2 years ago

8 0

Could you write the question more properly?

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(3.8 x 10 ^ -6) x (2.37 x 10 ^ -3)<br><br> Enter the answer in science notification

Black_prince [1.1K]

Multiply the coefficients and the powers of 10 with each other:

$(3.8 \times 10^{-6}) \times (2.37 \times 10^{-3}) = (3.8\times2.37) \times (10^{-6} \times10^{-3})$

The numeric part simply yields

$3.8\times2.37 = 9.006$

As for the powers of 10, you have to add the exponents, using the rule

$a^b \times a^c = a^{b+c}$

So, we have

$10^{-6} \times10^{-3} = 10^{-6-3} = 10^{-9}$

So, the final answer is

$9.006\times 10^{-9}$

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5. The coefficient of x7 in the polynomial then7x17 - 17x11 + 27x5 - 7 is​

5. The coefficient of x7 in the polynomial then7x17 - 17x11 + 27x5 - 7 is