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snow_lady [41]
3 years ago
7

How much longer is 2 1/2 inch long piece than a 2/5 inch long piece of string

Mathematics
1 answer:
tino4ka555 [31]3 years ago
3 0

two and one tenth longer

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The side lengths could be 4 in. x 16 in. because that equals 64 inches^2. It could also be 8 in. x 8 in. because that also equals 64 inches^2.
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8\frac{1}{5} acres

Step-by-step explanation:

7\frac{1}{4} + 3\frac{1}{5} - 2 \frac{1}{4}   \\\\7\frac{1}{4} - 2 \frac{1}{4}  = 5\\\\then:\\\\7\frac{1}{4} + 3\frac{1}{5} - 2 \frac{1}{4}  = 5 + 3\frac{1}{5} = 8 \frac{1}{5}

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The map shows locations of a new town. Circle the correct ordered pair for each location.
dlinn [17]

Answer:

library 2,3

park 8,2

market 3,7

red centers 4,10

pool 6,6

movie theater 9,9

ice cream shop 5,4

6 0
3 years ago
En el estante de un negocio hay 2 tipos de tarros de la misma mermelada y marca. El tarro más alto tiene el doble de altura que
Ipatiy [6.2K]

Answer:

tarro corto

Step-by-step explanation:

Aquí tenemos que comprar el frasco que tiene el menor costo por volumen.

h_1 = Altura del frasco corto

h_2 = La altura del frasco alto es el doble que el del frasco corto. = 2h_1

d_1 = Diámetro del frasco corto

d_2 = El diámetro del frasco alto es la mitad del frasco corto = \dfrac{1}{2}d_1

El volumen de un cilindro es \pi \dfrac{d^2}{4}h

La razón de los volúmenes de los frascos es

\dfrac{V_1}{V_2}=\dfrac{\pi\dfrac{d_1^2}{4}h_1}{\pi\dfrac{d_2^2}{4}h_2}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{d_1^2h_1}{d_2^2h_2}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{d_1^2h_1}{(\dfrac{1}{2}d_1)^22h_1}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{d_1^2h_1}{\dfrac{1}{4}d_1^22h_1}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{1}{\dfrac{1}{2}}\\\Rightarrow \dfrac{V_1}{V_2}=2\\\Rightarrow V_1=2V_2

El costo del frasco corto por unidad de volumen es

\dfrac{8000}{V_1}=\dfrac{8000}{2V_2}=\dfrac{4000}{V_2}

El costo del frasco alto por unidad de volumen es

\dfrac{4500}{V_2}=\dfrac{4500}{V_2}

\dfrac{4000}{V_2}

Entonces, el costo del frasco corto por unidad de volumen es menor que el costo por unidad de volumen del frasco alto.

Por lo tanto, deberíamos tomar el frasco corto.

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3 years ago
3x-4y=16 and 5x+2y=44 using elimination strategy and comparing strategy
chubhunter [2.5K]

3x-4y=16 \\5x+2y=44 \\ \\3x-4y=16 \\10x+4y=88 \\ \\13x=104 \\x=\boxed{104\div13=8}\\ \\3\times8-4y=16 \\24-4y=16 \\-4y=-8 \\y=\boxed{2}

5 0
3 years ago
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