The graph would be the normal parent function of f(x) but all points would be 6 units up.
There's an upward vertical shift of 6. To graph this, you need to graph the function f(x) and then add 6 units to all the y values.

Part A
To find the ticket price when the price is $16
Let us substitute the value of t = 16
p = -10 x (16 x16) + 500 x 16 + 60
p = -2560 + 8000 + 60
p =$ 5500
Part B
To get the maximum profit, we will have to differentiate P with respect to t

The maximum profit will be obtained when the derivative is zero
-20t + 500 = 0
20t = 500
t = 500/20
t = 25
This means that the ticket price has to be $25 so as to obtain the maximum price
Part C
The maximum profit will be obtained by substituting t = 25 into the original equation
let's bear in mind that a year has 12 months, so 30 months is really 30/12 years.

One of the loans is 3750 dollars and the other loan is 2250 dollars and when you add them together they make 6000.
Odds of rolling a 6 is 1/6. the odds of rolling another 6 is still 1/6. the number on the first toss has no effect on the second (this is called independent events) so you multiply the probabilities together
1/6 * 1/6 = 1/36