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Minchanka [31]
3 years ago
8

Write the slope-intercept form of the equation

Mathematics
1 answer:
evablogger [386]3 years ago
8 0

Answer:

y = -x-5

your welcome!

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Find the equation of a circle with a center at (7,2) and a point on the circle at (2,5)?
monitta

Answer:

(x-7)^2+(y-2)^2=34

Step-by-step explanation:

We want to find the equation of a circle with a center at (7, 2) and a point on the circle at (2, 5).

First, recall that the equation of a circle is given by:

(x-h)^2+(y-k)^2=r^2

Where (<em>h, k</em>) is the center and <em>r</em> is the radius.

Since our center is at (7, 2), <em>h</em> = 7 and <em>k</em> = 2. Substitute:

(x-7)^2+(y-2)^2=r^2

Next, the since a point on the circle is (2, 5), <em>y</em> = 5 when <em>x</em> = 2. Substitute:

(2-7)^2+(5-2)^2=r^2

Solve for <em>r: </em>

<em />(-5)^2+(3)^2=r^2<em />

Simplify. Thus:

25+9=r^2

Finally, add:

r^2=34

We don't need to take the square root of both sides, as we will have the square it again anyways.

Therefore, our equation is:

(x-7)^2+(y-2)^2=34

4 0
2 years ago
Given z=4+3i evaluate z​
DerKrebs [107]

Answer:

5

Step-by-step explanation:

Assuming we want to evaluate |z|, given that, z=4+3i.

Then, by definition of modulus,

|x + yi|  =  \sqrt{ {x}^{2} +  {y}^{2}  }

|4+ 3i|  =  \sqrt{ {4}^{2} +  {3}^{2}  }

|4+ 3i|  =  \sqrt{ 16+  9 }  \\ |4+ 3i|  =  \sqrt{25 }  \\ |4+ 3i|  = 5

Therefore the modulus be of the given complex number is 5 units

5 0
3 years ago
Help if you’re good at math I’ll give brainliest
boyakko [2]

Answer:

(4,2)

Step-by-step explanation:

Just by looking at the graph, you can see that they intersect at (4,2). But just to check:

x - 2 = -0.5x + 4

1.5x = 6

x = 4

y = 4 - 2 = 2

(4,2)

6 0
3 years ago
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Priscilla works at a cosmetics store. She recieves a weekly salary of $350 and is paid a 3% commission on weekly sales over $150
jarptica [38.1K]
What is the question?
6 0
3 years ago
Please help if you know the answer.....
andre [41]
I’m not really sure but I would say c
8 0
3 years ago
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