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3 years ago

Q3. If I = (P × R × T)/100, find T if I = 80 Rs, P = 400 Rs., R = 10 Rs. (2)

Mathematics

2 answers:

sukhopar [10]3 years ago

4 0

9514 1404 393

Answer:

T = 2

Step-by-step explanation:

Fill in the given numbers and solve for T.

I = PRT/100

80 = 400·10·T/100

80 = 40T . . . . . . . . . . . . simplify

80/40 = T = 2 . . . . . . . . divide by the coefficient of T

oksano4ka [1.4K]3 years ago

4 0

Answer:

2 years

Step-by-step explanation:

I = 80 Rs, P = 400 Rs, R = 10 Rs

I = (P * T * R)/100

80 = 400 * T * 10/100

80 = 40 * T

T = 2 years

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Veseljchak [2.6K]

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Suppose a normal distribution has a mean of 62 and a standard deviation of4. What is the probability that a data value is betwee

saw5 [17]

SOLUTION

From the given data the mean is 62 and standard deviation is 4

It is required to find the probability that a data value is between 57 and 62

That is:

$P(57\lt x\lt65)$

The z scores is calculated using:

$z=\frac{x-\mu}{\sigma}$

Using the x values it follows:

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Thus the required probability is:

$P(-1.25The proability is:[tex]P(-1.25This can be expressed as percentage as:[tex]P(-1.25\lt z\lt0.75)=66.8\%$

Therefore the correct option is C

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1 year ago