3 years ago

Write a rule for the nth term of the geometric sequence: a3=54, a6=1458

Mathematics

1 answer:

Shalnov [3]3 years ago

3 0

Answer:

tn = -1350 + 468n

Step-by-step explanation:

First, we need to find the difference.

1458 - 54 / 6 - 3

= 468

Now we need to find the first term.

t3 = t1 + (n - 1) (d)

54 = t1 + (3 - 1)(468)

54 = t1 + (2)(468)

54 = t1 + 936

-882 = t1

The rule is:

tn = -882 + (n-1) (468)

tn = -882 + 468n - 468

tn = -1350 + 468n

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