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Butoxors [25]
3 years ago
12

Write a rule for the nth term of the geometric sequence: a3=54, a6=1458

Mathematics
1 answer:
Shalnov [3]3 years ago
3 0

Answer:

tn = -1350 + 468n  

Step-by-step explanation:

First, we need to find the difference.

1458 - 54 / 6 - 3

= 468

Now we need to find the first term.

t3 = t1 + (n - 1) (d)

54 = t1 + (3 - 1)(468)

54 = t1 + (2)(468)

54 = t1 + 936

-882 = t1

The rule is:

tn = -882 + (n-1) (468)

tn = -882 + 468n - 468

tn = -1350 + 468n  

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guajiro [1.7K]

The given function is,

y=-5\cos (\frac{\pi}{2}(x-3))+6

The graph can be drawn as,

The period will be distance between two consequetive maximas,

\text{Period}=1-(-3)=4

Thus, period is correct.

The amplitude can be determined as,

\begin{gathered} Amplitude=\frac{\max -\min }{2} \\ =\frac{11-1}{2} \\ =5 \end{gathered}

Thus, amplitue is incorrect.

The range is,

y\in\lbrack1,11\rbrack

Thus, the range is correct.

The midline is,

\begin{gathered} \text{midline}=\frac{\max +\min }{2} \\ =\frac{1+11}{2} \\ =6 \end{gathered}

Thus, the midline is correct.

Thus, option (b) is the solution.

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Find an explicit formula for the arithmetic sequence below.<br> 9, 39/4, 21/2, 45/4, 12, 51/4,...
RideAnS [48]
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Are both 7 and -½ integers? why or why not?​
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Answer:

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Answer:

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