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3 years ago

15

A submarine descended 1500 meters below the surface of the water. It then rose 600 meters and then descended 150 meters. What wa

s the submarine's net gain or loss in altitude?

1 answer:

dem82 [27]3 years ago

5 0

Net loss:1050 m

1500-600+150

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There were 42 students who took a test in mathematics.there were 36 students who passed test 1, and there were 38 who passed tes

Keith_Richards [23]

We are giiven with two realms: 36 students who passed test 1 and <span>38 who passed test 2 in which 42 students overall took the test. to determine U' or those who didn't pass either of the tests, then we use the formula:
A or B = (A+B)-AandB
A/B = (36+38)-AandB= 74-AandB
42 = A+ B - AandB + U'; 42 = 74- AandB+ U'

where U' is the number who did not pass

U'= -32 + AandB
U' cannot be negative but can be zero,
AandB = 32 @ minimum number of those who fail.
AandB cannot be greater than 38 but can be greater than 36, hence
U' = -32 + 38 @ maximum number of those who fail.

Answer then is 6.

</span>

7 0

3 years ago

What is the value of x and y?

ladessa [460]

Answer:

x=16 and y=9

Step-by-step explanation:

2y+30=3y+21[Diagonals of parallelogram are equal]

30-21=3y-2y

y=9

3y=2x-5[Diagonals of parallelogram are equal]

3×9=2x-5

27=2x-5

2x=27+5

x=32/2=16

5 0

2 years ago

I’m stumped, can anyone please help me understand this

rodikova [14]

Answer:

<em><u>B. Store T sells apples at the lowest rate</u></em>

Step-by-step explanation:

Store R sells apples at $1.20 <u>per pound.</u>

Store S sells <u>4 pounds</u> of apples at $5.00.

Store T sells <u>3 pounds</u> of apples at $3.48.

To find the answer, <u>you have to find the unit price</u> for both Store S and Store T.

For Store S: 4 pounds = $5. <u>Divide the cost by the pounds</u>. This will give us <u>$1.25 per pound.</u>

For Store T: 3 pounds = $3.48. Same thing as Store S, d<u>ivide the cost by the number of pounds</u>. This will give us <u>1.16 per pound</u>.

Now, we know the unit prices for each store. It's time to answer the question.

A. Store R sells apples at the lowest rate.

This is <em><u>incorrect</u></em> because the store that sells the apples at the lowest rate is Store T.

B. Store T sells the apples at the lowest rate.

This answer is <em><u>correct</u></em>, but I'll also take a look at the other two

C. Store S charges a lower rate for apples than Store T.

Again, this is <em><u>incorrect</u></em> because Store T sells apples at the lowest rate.

D. Store T charges the same rate for apples as Store R.

<em><u>Nope</u></em>, Store T sells the apples at a lower rate than Store R.

This means your answer will be <u>B. Store T sells apples at the lowest rate</u>.

<h2>I hope this helped you understand the question!</h2>

6 0

3 years ago

Find the surface area of x^2+y^2+z^2=9 that lies above the cone z= sqrt(x^@+y^2)

Mashcka [7]

The cone equation gives

$z=\sqrt{x^2+y^2}\implies z^2=x^2+y^2$

which means that the intersection of the cone and sphere occurs at

$x^2+y^2+(x^2+y^2)=9\implies x^2+y^2=\dfrac92$

i.e. along the vertical cylinder of radius $\dfrac3{\sqrt2}$ when $z=\dfrac3{\sqrt2}$ .

We can parameterize the spherical cap in spherical coordinates by

$\mathbf r(\theta,\varphi)=\langle3\cos\theta\sin\varphi,3\sin\theta\sin\varphi,3\cos\varphi\right\rangle$

where $0\le\theta\le2\pi$ and $0\le\varphi\le\dfrac\pi4$ , which follows from the fact that the radius of the sphere is 3 and the height at which the sphere and cone intersect is $\dfrac3{\sqrt2}$ . So the angle between the vertical line through the origin and any line through the origin normal to the sphere along the cone's surface is

$\varphi=\cos^{-1}\left(\dfrac{\frac3{\sqrt2}}3\right)=\cos^{-1}\left(\dfrac1{\sqrt2}\right)=\dfrac\pi4$

Now the surface area of the cap is given by the surface integral,

$\displaystyle\iint_{\text{cap}}\mathrm dS=\int_{\theta=0}^{\theta=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}\|\mathbf r_u\times\mathbf r_v\|\,\mathrm dv\,\mathrm du$
$=\displaystyle\int_{u=0}^{u=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}9\sin v\,\mathrm dv\,\mathrm du$
$=-18\pi\cos v\bigg|_{v=0}^{v=\pi/4}$
$=18\pi\left(1-\dfrac1{\sqrt2}\right)$
$=9(2-\sqrt2)\pi$

3 0

3 years ago

15 POINTS ANSWER ASAP, SHOW WORK

forsale [732]

Answer:

$V=97.6\ in^3$

Step-by-step explanation:

step 1

Find the volume of the cylinder

The volume of the cylinder is equal to

$V=\pi r^{2}h$

we have

$r=4/2=2\ in$ ---> the radius is half the diameter

$h=8\ in$

substitute

$V=\pi (2)^{2}(8)\\\\V=32\pi\ in^3$

step 2

Find the volume of the cone

The volume of the cone is equal to

$V=\frac{1}{3}\pi r^{2} h$

we have

we have

$r=2\ in$ ---> the radius is the same that the radius of the cylinder

$h=0.70\ in$

substitute

$V=\frac{1}{3}\pi (2)^{2} (0.70)\\\\V=0.93\pi\ in^3$

step 3

Find the volume of the plastic object

we know that

The volume of the plastic object is equal to the volume of the cylinder minus the volume of the cone

so

$V=32\pi-0.93\pi=31.07\pi\ in^3$

assume

$\pi=3.1416$

$V=31.07(3.1416)=97.6\ in^3$

8 0

2 years ago