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Aleksandr [31]
3 years ago
12

Suppose you know that ∠S and ∠Y are complementary, and that m∠S = 4(m∠Y) − 210°. Find m∠Y.

Mathematics
1 answer:
EleoNora [17]3 years ago
4 0

Answer:

angle Y= 60 degrees

Step-by-step explanation:

angle S + angle Y = 90 degrees because they are complementary

Y = 90 - S

angle S = 4(Y)-210

substitute for Y

S = 4(90 - S) - 210

S = 360 - 4S - 210

reduce

5S = 150

S = 30

Y = 90 - 30 = 60

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Nikolay [14]
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4 0
3 years ago
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Given: a = 9, c = 5, B = 120 <br><br> b=
Zinaida [17]
B = 120 because it is in your sum
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Between the time Iko woke up and lunchtime,the temperature rose by 11.Then by the time he went to bed,the temperature dropped by
dimaraw [331]

Answer:

<u></u>

  • <u>11 + ( - 14)</u>

Explanation:

The complete question is:

<em>Between the time iko woke up and lunchtime, the temperature rose by 11º. Then by the time he went to bed, the temperature dropped by 14º.</em>

<em />

<em>Write an addition expression for the temperature relative to when iko woke up. </em>

<em />

<h2>Solution</h2>

It is said that between the time Iko woke up and lunchtime, the temperature rose by 11 degrees. A rise means the temperature increased and you must add 11º.

Then, relative to when Iko woke up the temperature is:

  • + 11º

Then, by the time Iko went to bed, the temperature dropped by 14º. A drop means that the change is negative. This means that you must add a negative number, and the additive expression is:

  • +  11º + (- 14º).

If you want the overall change in temperature you do the operation:

  • 11 + (-14) =  11 - 14 = - 3. A net decrease of 3º.

But the answer to this question is the additive expression:

  • 11 + ( - 14) ← answer
4 0
3 years ago
Find an exact value. Cos 75° negative square root of six plus square root of two quantity square root of six minus square root o
ehidna [41]

Answer:

√2(√3 - 1)/4

Step-by-step explanation:

To find an exact value for Cos75°, we use the compound angle formula. Since 75° = 45° + 30°, Cos75° = Cos(45° + 30°).

Using Cos(A + B) = CosACosB - SinASinB where A = 45° and B = 30°,  

Cos75° = Cos(45° + 30°) = Cos45°Cos30° - Sin45°Sin30°

Now Cos45° = Sin45° = 1/√2 = √2/2, Cos30° = √3/2 and Sin30° = 1/2.

Substituting these values into the above equation, we have

Cos75° = Cos(45° + 30°)

= Cos45°Cos30° - Sin45°Sin30°

= √2/2 × √3/2 -  √2/2 × 1/2

= √6/4 -√2/4

= √2(√3 - 1)/4

6 0
3 years ago
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