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steposvetlana [31]
3 years ago
12

Hi can you please help and do the ones in red i got them wrong copy and paste then add your answer :)

Mathematics
1 answer:
max2010maxim [7]3 years ago
3 0

Answer:

1. 14

2. 10

3. 7:6

5. 21

6. 10:7

I cant see 7-10

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Point H is the midpoint of side FK. Triangles F G H and K J H are connected at point H. The lengths of sides F H and H K are con
earnstyle [38]

Answer:

the answer would be x=6

to find it you would set 3x-2 equal to 2x+4 and solve because the two sides would be equal if the triangles are congruent

hope this helps :)

Step-by-step explanation:

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2 years ago
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Enter the value of p so the expression 5/6 - 1/3n is equivalent to p(5-2n)
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Greg needs $51 to go on a field trip. He has saved $12.75. He earns $6.50 per hour cleaning his neighbor's garden, and he earns
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3 years ago
Hi I'm the mom I would like to see if you can help me with this problem
Tanya [424]

From the statement of the problem, we know that:

• a train starts at City A and travels 2,158 km to City B,

,

• then it travels 3,793 km from City B to City C.

The distance between City A and City C is equal to the sum of the distance from City A to City B, and the distance from City B to City C. So the distance between City A and City C is 2,158 km + 3,793 km = 5951 km.

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5 0
1 year ago
A boat traveled 210 miles downstream and back. The trip downstream took 10 hours. The trip back took 70 hours. What is the speed
musickatia [10]

Try this solution:

Answer: 6 & 4.5 (m-per-h)

Step-by-step explanation:

- The basic formula used in this task is S=V*t, where S - distance, V - speed, t - time.

- the downstream speed is: V+Vc, where V - the speed of the boat in still water, Vc - the speed of the current.

- the upstream speed is: V-Vc.

- according to the described above the distance for downstream is S1=(V+Vc)*t1, where t1=10; the distance for upstream is S2=(V-Vc)*t2, where t2=70.

- for whole travel down- and upstream: S=S1+S2.

- Using these it is possible to make up the system of the equations:

\left \{ {{(70(V-V_c)=10(V+V_c)} \atop {70(V-V_c)+10(V+V_c)=210}} \right.

V - the speed of the boat in still water - 6 miles per hour, Vc - the speed of the current - 4.5 miles per hour. All the details for the system of the equations are in the attachment.

4 0
3 years ago
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