The weight of each cabbage is not given.
I'll assume that each cabbage weighs p pounds.
Now, we know that Yasmin bought 6 cabbage each weighing p pounds. To know the total weight, we will simply multiply the number of cabbages by the weight of each as follows:
Total weight = 6 * p = 6p pounds
Hope this helps :)
Answer: 40:27
Step-by-step explanation: 80:54 / 2:2 = 40:27
Answer:
![\left(\displaystyle \sqrt[3]{x^{-\tfrac 35}}\right)^{\tfrac 58}](https://tex.z-dn.net/?f=%5Cleft%28%5Cdisplaystyle%20%5Csqrt%5B3%5D%7Bx%5E%7B-%5Ctfrac%2035%7D%7D%5Cright%29%5E%7B%5Ctfrac%2058%7D)
Step-by-step explanation:
![\left(\displaystyle \sqrt[3]{x^{-\tfrac 35}}\right)^{\tfrac 58}\\\\\\=\left[ \left(\displaystyle x^{-\tfrac 35} \right)^{\tfrac 13 \right]^{\tfrac 58}\\\\\\=\left( \displaystyle x^{-\tfrac 35}\right)^{\tfrac 5{24}}\\\\\\=x^{ \displaystyle -\tfrac{3}{24} \right}\\\\\\=x^{\displaystyle -\tfrac 18 }\\\\\\=\dfrac 1{x^{\tfrac 18}}](https://tex.z-dn.net/?f=%5Cleft%28%5Cdisplaystyle%20%5Csqrt%5B3%5D%7Bx%5E%7B-%5Ctfrac%2035%7D%7D%5Cright%29%5E%7B%5Ctfrac%2058%7D%5C%5C%5C%5C%5C%5C%3D%5Cleft%5B%20%5Cleft%28%5Cdisplaystyle%20x%5E%7B-%5Ctfrac%2035%7D%20%5Cright%29%5E%7B%5Ctfrac%2013%20%5Cright%5D%5E%7B%5Ctfrac%2058%7D%5C%5C%5C%5C%5C%5C%3D%5Cleft%28%20%5Cdisplaystyle%20x%5E%7B-%5Ctfrac%2035%7D%5Cright%29%5E%7B%5Ctfrac%205%7B24%7D%7D%5C%5C%5C%5C%5C%5C%3Dx%5E%7B%20%5Cdisplaystyle%20-%5Ctfrac%7B3%7D%7B24%7D%20%20%5Cright%7D%5C%5C%5C%5C%5C%5C%3Dx%5E%7B%5Cdisplaystyle%20-%5Ctfrac%2018%20%20%7D%5C%5C%5C%5C%5C%5C%3D%5Cdfrac%201%7Bx%5E%7B%5Ctfrac%2018%7D%7D)
The Canadian dollar is .72 of a American dollar so the answer has to be B.
<h3>
Answer:</h3>
C. 4(x-3)-x
<h3>
Step-by-step explanation:</h3>
All of the given expressions are equivalent to 3x+12 except selection C. Using that in your equation makes it be ...
... 3(x +1) +9 = 4(x -3) -x
... 3x +12 = 3x -12
... 12 = -12 . . . . . <em>false</em>
There is no value of x that will make this true, hence NO SOLUTION.
_____
<em>Comment on the other choices</em>
3x+12 = 3x+12 has an <em>infinite number of solutions</em>, as <u><em>any</em></u> value of x will make this true.
