Hi student, let me help you out! :)
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We are asked to simplify the expression
.
![\triangle~\fbox{\bf{KEY:}}](https://tex.z-dn.net/?f=%5Ctriangle~%5Cfbox%7B%5Cbf%7BKEY%3A%7D%7D)
That's exactly what we need to do - combine like terms.
So, we subtract:
![\star~\large\pmb{7x^2-x^2}](https://tex.z-dn.net/?f=%5Cstar~%5Clarge%5Cpmb%7B7x%5E2-x%5E2%7D)
Which gives us:
![\star~\large\pmb{6x^2}](https://tex.z-dn.net/?f=%5Cstar~%5Clarge%5Cpmb%7B6x%5E2%7D)
Hope it helps you out! :D
Ask in comments if any queries arise.
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Answer:
The correct option is B.
Step-by-step explanation:
Given information: AB\parallel DCAB∥DC and BC\parallel ADBC∥AD .
Draw a diagonal AC.
In triangle BCA and DAC,
AC\cong ACAC≅AC (Reflexive Property of Equality)
\angle BAC\cong \angle DCA∠BAC≅∠DCA ( Alternate Interior Angles Theorem)
\angle BCA\cong \angle DAC∠BCA≅∠DAC ( Alternate Interior Angles Theorem)
The ASA (Angle-Side-Angle) postulate states that two triangles are congruent if two corresponding angles and the included side of are congruent.
By ASA postulate,
\triangle BCA\cong \triangle DAC△BCA≅△DAC
Therefore option B is correct
Acute angle i think about 60
(x – h)² + (y – k)²<span> = r</span>²
Fill in the numbers
(x – 7)²<span> + (y +3)</span>²<span> = 49</span>
A = 15000(1.04)6 .........You can put this into your calculator such that it becomes
A = $18,979.79