All categories

2 years ago

Damell had 27 coins in his pocket. He lost some. Write an expression that shows how many coins Darell lost.

Mathematics

1 answer:

Salsk061 [2.6K]2 years ago

3 0

Answer:

esl b comafio qe vasu slair beniaen

Step-by-step explanation:

You might be interested in

ASAP PLEASE I WILL MAKE YOU BRAINLIEST!!!!

Pie

Answer:

Sarah bought 3 first class tickets and 3 coach tickets.

Step by Step Explanation:

1030+1030+1030=3850

380+380+380=1140

3850+1140=4230

7 0

3 years ago

PLEASE HELPPPPP

Flauer [41]

Answer:

Cost of 1 rose bush = x = $5

Cost of 1 geraniums = y = $2

Step-by-step explanation:

DeShawn and Mike each improved their yards by planting rose bushes and geraniums. They bought their supplies from the same store.

Let us represent:

Cost of 1 rose bush = x

Cost of 1 geraniums = y

DeShawn spent $13 on 1 rose bush and 4 geraniums.

x + 4y = 13..... Equation 1

x = 13 - 4y

Mike spent $56 on 10 rose bushes and 3 geraniums.

10x + 3y = 56....... Equation 2

We substitute 13 - 4y for x in Equation 2

10(13 - 4y) + 3y = 56

130 - 40y + 3y = 56

Collect like terms

- 40y + 3y = 56 - 130

-37y = -74

y = -74/37

y = $2

Solving for x

x = 13 - 4y

x = _13 - 4 × $2

x = $13 - $8

x = $5

Therefore,

Cost of 1 rose bush = x = $5

Cost of 1 geraniums = y = $2

7 0

3 years ago

Match the circle equations in general form with their corresponding equations in standard form. Not all will be used.

Xelga [282]

The standard form of the equation of a circumference is given by the following expression:

 $(x-h)^{2}+(y-k)^{2}=r^{2} \\ \\ where \ (h, k) \ is \ the \ center \ of \ the \ circumference \ and \ r \ the \ radius$

On the other hand, the general form is given as follows:

 $x^{2}+y^{2}+Dx+Ey+F=0 \\ \\ where: \\ D=-2h, \ E=-2k, \ F=h^{2}+k^{2}-r^{2}$ 

In this way, we can order the mentioned equations as follows:

Equations in Standard Form:

 $\bold{a)} \ (x-6)^{2}+(y-4)^{2}=56 \\ \bold{b)} \ (x-2)^{2} + (y+6)^{2}=60 \\ \bold{c)} \ (x+2)^{2}+(y+3)^{2}=18 \\ \bold{d)} \ (x+1)^{2}+(y-6)^{2}=46$

Equations in General Form:

$\bold{1)} \ x^{2}+y^{2}-4x+12y-20=0 \\ \bold{2)} \ x^{2}+y^{2}+6x-8y-10=0 \\ \bold{3)} \ 3x^{2}+3y^{2}+12x+18y-15=0 \\ \\ If \ we \ divide \ this \ equation \ by \ 3, \ the \ equation \ becomes: \\ x^{2}+y^{2}+4x+6y-5=0 \\ \\ \bold{4)} \ 5x^{2}+5y^{2}-10x+20y-30=0 \\ \\ If \ we \ divide \ this \ equation \ by \ 5, \ the \ equation \ becomes: \\ x^{2}+y^{2}-2x+4y-6=0 \\ \\ \bold{5)} \ 2x^{2}+2y^{2}-24x-16y-8=0 \\ \\ If \ we \ divide \ this \ equation \ by \ 2, \ the \ equation \ becomes: \\ x^{2}+y^{2}-12x-8y-4=0$

$\bold{6)} \ x^{2}+y^{2}+2x-12y$

So let's match each equation:

$\bold{From \ a)} \\ \\ (h,k)=(6,4),\ r=2\sqrt{14} \\ D=-12, \ E=-8 \\ F=-4$

Then, its general form is:

$x^{2}+y^{2}-12x-8y-4=0$

First. a) matches 5) 

$\bold{From \ b)} \\ \\ (h,k)=(2,-6),\ r=2\sqrt{15} \\ D=-4, \ E=12 \\ F=-20$

Then, its general form is:

$x^{2}+y^{2}-4x+12y-20=0$

Second. b) matches 1) 

$\bold{From \ c)} \\ \\ (h,k)=(-2,-3),\ r=3\sqrt{2} \\ D=4, \ E=6 \\ F=-5$

Then, its general form is:

$x^{2}+y^{2}+4x+6y-5=0$

Third. c) matches 3)

$\bold{From \ d)} \\ \\ (h,k)=(-1,6),\ r=\sqrt{46} \\ D=2, \ E=-12, \ F=-9$

Then, its general form is: $x^{2}+y^{2}+2x-12y-9=0$

Fourth. d) matches 6)

6 0

3 years ago

Read 2 more answers

Ryan wants to rent a limo for a trip to the city. The limo costs $700 for the night and $2.50 per mile. What is the greatest dis

Pavel [41]

Answer:

20 miles

Step-by-step explanation:

the answer is 20 miles

5 0

3 years ago

Read 2 more answers