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oee [108]
3 years ago
13

Help please I’ll give extra points

Mathematics
1 answer:
romanna [79]3 years ago
8 0

Answer:

56

Step-by-step explanation:

180-124 ....................

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A company that makes cola drinks states that the mean caffeine content per​ 12-ounce bottle of cola is 35 milligrams. You want t
Ne4ueva [31]

Answer:

The pvalue of the test is 0.177 > 0.02, which means that at α=0.02, you cannot reject the company's claim.

Step-by-step explanation:

A company that makes cola drinks states that the mean caffeine content per​ 12-ounce bottle of cola is 35 milligrams. You want to test this claim.

At the null hypothesis, you test that the mean caffeine content is of 35 milligrams, that is:

H_o: \mu = 35

And at the alternate hypothesis, you test if the content is different from 35, so:

H_a: \mu \neq 35

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

35 is tested at the null hypothesis:

This means that \mu = 35

During your​ tests, you find that a random sample of thirty​ 12-ounce bottles of cola has a mean caffeine content of 36.8 milligrams. Assume the population is normally distributed and the population standard deviation is 7.3 milligrams.

This means that n = 30, X = 36.8, \sigma = 7.3

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{36.8 - 35}{\frac{7.3}{\sqrt{30}}}

z = 1.35

Pvalue of the test and decision:

The pvalue of the test is the probability of the mean caffeine content differing from the mean by at least 36.8 - 35 = 1.8, which is P(|z| > 1.35), which is 2 multiplied by the pvalue of z = -1.35.

Looking at the z = -1.35 has a pvalue of 0.0885

2*0.0885 = 0.177

The pvalue of the test is 0.177 > 0.02, which means that at α=0.02, you cannot reject the company's claim.

5 0
3 years ago
You deposit $50 in your savings account. One week later, you withdraw $20. Write each amount as an integer
Sloan [31]
Deposit mean add 50, then withdraw means taking out 20, you do subtraction: $50-$20=$30

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3 years ago
Write the improper fraction as a mixed<br> number in its simplest form.<br><br> 32<br> —<br> 22
Nastasia [14]
32/22 is the improper fraction and it’s mixed number is 1 5/11 and it’s simplest form is 16/11
5 0
3 years ago
Read 2 more answers
Determine if the function is odd even or neither calculator
BlackZzzverrR [31]
It is not odd or even.  It is neither.  It's a calculator.
5 0
3 years ago
A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. ​(a) Describe the
Ivanshal [37]

Answer:

a) \bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})

With:

\mu_{\bar X}= 83

\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3

b) z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2

P(Z>2) = 1-P(Z

c) z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45

P(Z

d) z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1

z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2

P(-1.2

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

\mu = 83, \sigma = 27

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})

With:

\mu_{\bar X}= 83

\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3

Part b

We want this probability:

P(\bar X>89)

We can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score for 89 we got:

z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2

P(Z>2) = 1-P(Z

Part c

P(\bar X

We can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score for 75.65 we got:

z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45

P(Z

Part d

We want this probability:

P(79.4 < \bar X < 89.3)

We find the z scores:

z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1

z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2

P(-1.2

8 0
4 years ago
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