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oee [108]
3 years ago
13

Help please I’ll give extra points

Mathematics
1 answer:
romanna [79]3 years ago
8 0

Answer:

56

Step-by-step explanation:

180-124 ....................

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How do you write out in word form 233,740
allsm [11]
The answer is two hundred thirty-three thousand seven hundred forty.
Hope that helped you!
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Use a transformation to solve the equation. t – (–16.5) = –13.4 A. t = –29.9 B. t = –3.1 C. t = 3.1 D. t = 29.9
Kipish [7]
<span>t – (–16.5) = –13.4
t + 16.5 = -13.4
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(01.02 MC)The number line shows the distance in meters of two jellyfish, A and B, from a predator located at point X:
expeople1 [14]

Answer:

The answer is C

Step-by-step explanation:

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3 years ago
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Will mark brainliest! Would also really appreciate it if someone could explain it as well!
guapka [62]

Answer:

sin (x) ≥ 0, between 0° and 180° or 0 and π,

sin(x) ≥ 1/2, between 30° and 150° or π/6 and 5π/6

Step-by-step explanation:

This is how I would do it. Subtract sin(x) from both sides

2sin^{2} (x) - sin(x) ≥ 0 , then factor out sin(x)

sin(x) [2 sin(x) - 1] ≥0, then set each factor ≥ 0

sin(x) ≥ 0 and 2 sin(x) - 1 ≥ 0

sin (x) ≥ 0, between 0° and 180° or 0 and π

2 sin(x) ≥ 1

sin(x) ≥ 1/2, between 30° and 150° or π/6 and 5π/6

6 0
3 years ago
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If sin a= 12/13 and tan B 8/15 and angles a and b are in qundrant 1 find the value of tan (a+b)
natali 33 [55]

Answer:

The value of Tan (a + b) is \frac{-220}{21} .

Step-by-step explanation:

Given as :

Tan b = \frac{8}{15}

Sin a = \frac{12}{13}

∵Sin Ф = \dfrac{\textrm perpendicular}{\textrm Hypotenuse}

So,  \dfrac{\textrm perpendicular}{\textrm Hypotenuse} =  \frac{12}{13}

Now, Base² = Hypotenuse² -  Perpendicular²

Or, Base² = 13² - 12²

Or,  Base² = 169 - 144

Or,  Base² = 25

∴     Base = \sqrt{25} = 5

And Tan Ф =  \dfrac{\textrm perpendicular}{\textrm Base}

Or, Tan a = \frac{12}{5}

Now, Tan (a + b) = \dfrac{Tan a + Tan b}{1- Tan a Tanb}

Or, Tan (a + b) = \frac{\frac{12}{5}+\frac{8}{5}}{1-(\frac{12}{5}\times \frac{8}{15})}

or, Tan (a + b) = \frac{\frac{36+8}{15}}{\frac{75-96}{75}}

or, Tan (a + b) =\frac{\frac{44}{15}}{\frac{-21}{75}}

Or, Tan (a + b) = \frac{-220}{21}

Hence The value of Tan (a + b) is \frac{-220}{21} . Answer

5 0
3 years ago
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