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11111nata11111 [884]
2 years ago
6

QUESTION 1: TRANSPORT Mr Dlamini transport people between Butterworth and East London using a bus which has a capacity of 100 pe

ople. The transport charge starts with a minimum charge of R8 and thereafter it was increased by R2 for each kilometre. On a particular day the bus was full with passengers from Butterworth. In each and every kilometre there was a passenger getting off while no new passenger entered in the bus. Mr Dlamini was calculating total money in his hand after each passenger was getting out. The total amount he has after each stop can be written as a series as follows: S. = 8 + 10 + 12 + 14 +... Use the series to calculate the following questions 1.1 (1) Term 2 (T2) = Sum of first two terms (S2) (2) (ii) Express T2 in terms of S, and S2. (1)​
Mathematics
1 answer:
Dvinal [7]2 years ago
5 0

From the series, it can be deduced that the sum of the first two terms will be 18.

<h3>How to calculate the series</h3>

From the information given, it was stated that the transport charge starts with a minimum charge of R8 and thereafter it was increased by R2 for each kilometre.

The series is also given as S. = 8 + 10 + 12 + 14 +... Therefore, the sum of the first two terms will be:

= 8 + 10

= 18

Expressing T2 in terms of S, and S2 will be T2 = S + S2.

Learn more about arithmetic series on:

brainly.com/question/24295771

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For his long distance phone service,Frank pays a $2 monthly fee plus 12 cents per minute.Last month, Franks long distance bill $
navik [9.2K]

Answer:

a total of 129 minutes

Step-by-step explanation:

$17.48 - $2 fixed monthly fee = $15.48

$15.48/0.12 = 129 minutes

8 0
3 years ago
In the early 1970's, Canada Post started using six-character postal codes. Each postal code uses three letters and three digits
pogonyaev
A Canadian postal code looks  like this:

                   K1A 3B1 .

So you have:  letter - digit - letter - digit - letter - digit .

The question doesn't say anything about restrictions on
which letters can be used, or restrictions on repeating letters
or digits within one postal code. So as far as we know, each
letter can be any one of 26, and each digit can be any one of 10.

The total number of possibilities would be

                 (26·10·26)  ·  (10·26·10)  =  17,576,000 .

In the real world, though, (or at least in Canada), Postal codes
don't include the letters D, F, I, O, Q or U, and the first letter
does not use W or Z. When you work it out with these restrictions,
it means there's a theoretical limit of 7.2 million postal codes.
The practical limit is a bit lower, as Canada Post reserves some
codes for special functions, such as for test or promotional purposes. 
One example is the code H0H 0H0 for Santa Claus !  Other special
codes are for sorting mail bound for destinations outside Canada.

At the present time, there are a little over 830,000 active postal codes.
That's about 12% of the total possibilities, so there are still plenty of codes
left for expansion.
4 0
3 years ago
Simplify the expression by combining like terms. 15+12−5+4−7
Anastasy [175]

Answer:

19

Step-by-step explanation:

15+12-5+4-7=

(15+12+4)-5-7=

(27+4)-5-7=

31-5-7=

31-12=

19

3 0
3 years ago
Find the surface area of the composite figure.
Sloan [31]

With the help of the <em>area</em> formulae of rectangles and triangles and the concept of <em>surface</em> area, the <em>surface</em> area of the composite figure is equal to 276 square centimeters.

<h3>What is the surface area of a truncated prism?</h3>

The <em>surface</em> area of the <em>truncated</em> prism is the sum of the areas of its six faces, which are combinations of the areas of rectangles and <em>right</em> triangles. Then, we proceed to determine the <em>surface</em> area:

A = (12 cm) · (4 cm) + 2 · (3 cm) · (4 cm) + 2 · (12 cm) · (3 cm) + 2 · 0.5 · (12 cm) · (5 cm) + (5 cm) · (4 cm) + (13 cm) · (4 cm)

A = 48 cm² + 24 cm² + 72 cm² + 60 cm² + 20 cm² + 52 cm²

A = 276 cm²

With the help of the <em>area</em> formulae of rectangles and triangles and the concept of <em>surface</em> area, the <em>surface</em> area of the composite figure is equal to 276 square centimeters.

To learn more on surface areas: brainly.com/question/2835293

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7 0
1 year ago
Figure 1 is a square pyramid. Figure 2 is a right triangular prism.
amm1812

Answer:

the answer is

The surface area of Figure 1 is <u>10.2</u> square centimeters <u>Less</u> than the surface area of Figure 2.

Step-by-step explanation:

Figure 1

area of a square = s2

=9squared

=81 sq cm

area of triangle = 1/2 bh

=1/2 (9cm) (14cm)

=63 sq. cm

find surface area

SA = 81 sq. cm + 4(63 sq. cm)

SA = 81 sq. cm + 252 sq. cm

SA = 333 sq. cm

Figure 2 Calculation

area of rectangle = lw

a = (12cm) (8 cm)

a = 96 sq. cm

area of triangle = 1/2 bh

=1/2 (8 cm) (6.9 cm)

= 27.6 sq. cm

total surface are of figure 2

SA = 3 (96 sq.cm) + 2 (27.6 sq. cm)

SA = 288 sq. cm + 55.2 sq. cm

SA = 343.2 sq. cm

find the difference between figure 1 and figure 2

343.2 sq. cm - 333 sq. cm = 10.2 sq. cm

5 0
3 years ago
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