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3 years ago

What are the coordinates of the circumcenter of this triangle?

Mathematics

2 answers:

Fed [463]3 years ago

8 0

<h2>Answer:</h2>

(0.5,0.5) is the coordinates of the circumcenter of the given triangle(Δ).

balu736 [363]3 years ago

5 0

Answer:

(0.5, 0.5)

Step-by-step explanation:

draw lines in the middle of each side and the points line up in one spot

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Slope of the line that contains (1,6) and (2, -2)

s2008m [1.1K]

1,4

it’s y1-y2
———-
x1-x2

8 0

3 years ago

Read 2 more answers

One factor in flood safety along a levee is the area that will absorb water should the levee break. The coordinates that make up

Anit [1.1K]

Let

$A(0,0)\\ B (2.8, 2.1)\\C(4.3, 4.4)$

using a graph tool

see the attached figure

The figure is a triangle

we know that

The Heron's Formula is a method for calculating the area of a triangle when you know the lengths of all three sides.

Hero's Formula is equal to

$Area=\sqrt{p*(p-a)*(p-b)*(p-c)}$

where

p is is half the perimeter of the triangle

a,b,c are the lengths of the sides of a triangle

Step $1$

Find the length sides of the triangle

a) Find the distance AB

$d =\sqrt{(y2-y1)^{2} +(x2-x1)^{2}}$

Substitute

$d =\sqrt{(2.1-0)^{2} +(2.8-0)^{2}}$

$d =3.5\ mi}$

b) Find the distance AC

$d =\sqrt{(y2-y1)^{2} +(x2-x1)^{2}}$

Substitute

$d =\sqrt{(4.4-0)^{2} +(4.3-0)^{2}}$

$d =6.15\ mi}$

c) Find the distance BC

$d =\sqrt{(y2-y1)^{2} +(x2-x1)^{2}}$

Substitute

$d =\sqrt{(4.4-2.1)^{2} +(4.3-2.8)^{2}}$

$d =2.75\ mi}$

Step $2$

Find the perimeter of the triangle

$Perimeter= 3.5+6.15+2.75 =12.4\ mi$

Find the half of the perimeter

$p=\frac{12.4}{2} = 6.2\ mi$

Step $3$

Find the area of the triangle

$Area=\sqrt{6.2*(6.2-3.5)*(6.2-6.15)*(6.2-2.75)}$

$Area=\sqrt{6.2*(2.7)*(0.05)*(3.45)}$

$Area= 1.69\ mi^{2}$

therefore

the answer is the option

a) 1.65 mi^2.

4 0

3 years ago

Read 2 more answers

Please help! Area of part of a circle!!!

Helga [31]

The sector (shaded segment + triangle) makes up 1/3 of the circle (which is evident from the fact that the labeled arc measures 120° and a full circle measures 360°). The circle has radius 96 cm, so its total area is π (96 cm)² = 9216π cm². The area of the sector is then 1/3 • 9216π cm² = 3072π cm².

The triangle is isosceles since two of its legs coincide with the radius of the circle, and the angle between these sides measures 120°, same as the arc it subtends. If b is the length of the third side in the triangle, then by the law of cosines

b² = 2 • (96 cm)² - 2 (96 cm)² cos(120°) ⇒ b = 96√3 cm

Call b the base of this triangle.

The vertex angle is 120°, so the other two angles have measure θ such that

120° + 2θ = 180°

since the interior angles of any triangle sum to 180°. Solve for θ :

2θ = 60°

θ = 30°

Draw an altitude for the triangle that connects the vertex to the base. This cuts the triangle into two smaller right triangles. Let h be the height of all these triangles. Using some trig, we find

tan(30°) = h / (b/2) ⇒ h = 48 cm

Then the area of the triangle is

1/2 bh = 1/2 • (96√3 cm) • (48 cm) = 2304√3 cm²

and the area of the shaded segment is the difference between the area of the sector and the area of the triangle:

3072π cm² - 2304√3 cm² ≈ 5660.3 cm²

7 0

3 years ago

11 more than four times a number is 39

Aliun [14]

Hello!

Your answer is: 7

(X = "A number")

"11 more than four times a number is 39" in equation form is: 4X + 11 = 39

to solve, first subtract 11 from both sides:

4X = 28

then divide both sides by 4 to get:

X = 7

I hope this helps, and have a nice day!

4 0

4 years ago

Round 1149 to the nearest thousand.

zysi [14]

1150, i’m pretty sure that’s it!

4 0

3 years ago