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3241004551 [841]
3 years ago
12

What type of triangle must the hanger be to hang clothes evenly?

Mathematics
1 answer:
navik [9.2K]3 years ago
7 0
Yes it an obtuse because the angle is 110
and its isosciles becaues the two 35 angles
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V = BH - 5 <br> How do I solve for b in this equation
Zolol [24]

Answer:

B=\frac{V+5}{H}

Step-by-step explanation:

Add 5 to both sides:

V+5=BH

Divide both sides by H:

B=\frac{V+5}{H}

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the debate team is showing a video of their recent debate. the first showing begins at 3:15 P.M. The second showing is scheduled
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The video will end at 4.20 PM (4.50 - 30 mins). So it starts at 3.15 PM and ends at 4.20 PM. So it is 1 hour and 5 minutes.
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True or false <br><br> A chance event with probability 1 is certain to happen
Gnesinka [82]

Answer:

True, since 1 is 1/1, which is 100%

<em>Hope that helps! :)</em>

Step-by-step explanation:

7 0
3 years ago
Please Complete the question.
Norma-Jean [14]

Answer:

0.0174 is the answer you are looking for

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2 years ago
If a coin is tossed three times, find probability of getting
Assoli18 [71]

{\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}

‣ A coin is tossed three times.

{\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}

‣ The probability of getting,

1) Exactly 3 tails

2) At most 2 heads

3) At least 2 tails

4) Exactly 2 heads

5) Exactly 3 heads

{\large{\textsf{\textbf{\underline{\underline{Using \: Formula :}}}}}}

\star \: \tt  P(E)= {\underline{\boxed{\sf{\red{  \dfrac{ Favourable \:  outcomes }{Total \:  outcomes}  }}}}}

{\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}

★ When three coins are tossed,

then the sample space = {HHH, HHT, THH, TTH, HTH, HTT, THT, TTT}

[here H denotes head and T denotes tail]

⇒Total number of outcomes \tt [ \: n(s) \: ] = 8

<u>1) Exactly 3 tails </u>

Here

• Favourable outcomes = {HHH} = 1

• Total outcomes = 8

\therefore  \sf Probability_{(exactly  \: 3 \:  tails)}  =  \red{ \dfrac{1}{8}}

<u>2) At most 2 heads</u>

[It means there can be two or one or no heads]

Here

• Favourable outcomes = {HHT, THH, HTH, TTH, HTT, THT, TTT} = 7

• Total outcomes = 8

\therefore  \sf Probability_{(at \: most  \: 2 \:  heads)}  =  \green{ \dfrac{7}{8}}

<u>3) At least 2 tails </u>

[It means there can be two or more tails]

Here

• Favourable outcomes = {TTH, TTT, HTT, THT} = 4

• Total outcomes = 8

\longrightarrow   \sf Probability_{(at \: least \: 2 \:  tails)}  =  \dfrac{4}{8}

\therefore  \sf Probability_{(at \: least \: 2 \:  tails)}  =   \orange{\dfrac{1}{2}}

<u>4) Exactly 2 heads </u>

Here

• Favourable outcomes = {HTH, THH, HHT } = 3

• Total outcomes = 8

\therefore  \sf Probability_{(exactly \: 2 \:  heads)}  =  \pink{ \dfrac{3}{8}}

<u>5) Exactly 3 heads</u>

Here

• Favourable outcomes = {HHH} = 1

• Total outcomes = 8

\therefore  \sf Probability_{(exactly \: 3 \:  heads)}  =  \purple{ \dfrac{1}{8}}

\rule{280pt}{2pt}

8 0
1 year ago
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